我正在努力使用HttpURLConnection和OutputStreamWriter。
代码实际到达服务器，因为我得到了有效的错误响应。发出POST请求，但服务器端没有收到任何数据。
任何有关正确使用此东西的提示都非常受欢迎。
代码在AsyncTask中
protected JSONObject doInBackground(Void... params) {
try {
url = new URL(destination);
client = (HttpURLConnection) url.openConnection();
client.setDoOutput(true);
client.setDoInput(true);
client.setRequestProperty("Content-Type", "application/json; charset=UTF-8");
client.setRequestMethod("POST");
//client.setFixedLengthStreamingMode(request.toString().getBytes("UTF-8").length);
client.connect();
Log.d("doInBackground(Request)", request.toString());
OutputStreamWriter writer = new OutputStreamWriter(client.getOutputStream());
String output = request.toString();
writer.write(output);
writer.flush();
writer.close();
InputStream input = client.getInputStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(input));
StringBuilder result = new StringBuilder();
String line;
while ((line = reader.readLine()) != null) {
result.append(line);
}
Log.d("doInBackground(Resp)", result.toString());
response = new JSONObject(result.toString());
} catch (JSONException e){
this.e = e;
} catch (IOException e) {
this.e = e;
} finally {
client.disconnect();
}
return response;
}
我想发送的JSON：
JSONObject request = {
"action":"login",
"user":"mogens",
"auth":"b96f704fbe702f5b11a31524bfe5f136efea8bf7",
"location":{
"accuracy":25,
"provider":"network",
"longitude":120.254944,
"latitude":14.847808
}
};
我从服务器得到的响应：
JSONObject response = {
"success":false,
"response":"Unknown or Missing action.",
"request":null
};
我应该有的回应：
JSONObject response = {
"success":true,
"response":"Welcome Mogens Burapa",
"request":"login"
};
服务器端PHP脚本：
<?php
$json = file_get_contents('php://input');
$request = json_decode($json, true);
error_log("JSON: $json");
error_log('DEBUG request.php: ' . implode(', ',$request));
error_log("============ JSON Array ===============");
foreach ($request as $key => $val) {
error_log("$key => $val");
}
switch($request['action'])
{
case "register":
break;
case "login":
$response = array(
'success' => true,
'message' => 'Welcome ' . $request['user'],
'request' => $request['action']
);
break;
case "location":
break;
case "nearby":
break;
default:
$response = array(
'success' => false,
'response' => 'Unknown or Missing action.',
'request' => $request['action']
);
break;
}
echo json_encode($response);
exit;
?>
Android Studio中的logcat输出：
D/doInBackground(Request)﹕ {"action":"login","location":{"accuracy":25,"provider":"network","longitude":120.254944,"latitude":14.847808},"user":"mogens","auth":"b96f704fbe702f5b11a31524bfe5f136efea8bf7"}
D/doInBackground(Resp)﹕ {"success":false,"response":"Unknown or Missing action.","request":null}
如果我将?action=login附加到URL，我可以从服务器获得成功响应。但只有action参数注册服务器端。
{"success":true,"message":"Welcome ","request":"login"}
结论必须是URLConnection.write(output.getBytes("UTF-8"));没有传输数据
好吧，数据毕竟是转移的。
@greenaps提供的解决方案可以解决问题：
$json = file_get_contents('php://input');
$request = json_decode($json, true);
上面的PHP脚本已更新以显示解决方案。
echo (file_get_contents('php://input'));
将显示json文本。使用它像：
$jsonString = file_get_contents('php://input');
$jsonObj = json_decode($jsonString, true);
尝试使用DataOutputStream而不是OutputStreamWriter。
DataOutputStream out = new DataOutputStream(_conn.getOutputStream());
out.writeBytes(your json serialized string);
out.close();
我让服务器告诉我它是从我那里得到的。
请求标题和POST正文
<?php
$requestHeaders = apache_request_headers();
print_r($requestHeaders);
print_r("\n -= POST Body =- \n");
echo file_get_contents( 'php://input' );
?>
奇迹般有效）
代码实际到达服务器，因为我得到了有效的错误响应。发出POST请求，但服务器端没有收到任何数据。
得到了同样的情况，来到@greenapps回答。你应该知道从'post request'收到什么服务器
我在服务器端做的第一件事：
echo (file_get_contents('php://input'));
然后在客户端打印/ Toast / show message response。确保其正确的形式，如：
{"username": "yourusername", "password" : "yourpassword"}
如果响应像这样（因为你用yourHashMap.toString()发布请求）：
{username=yourusername,password=yourpassword}
而不是使用.toString（），而是使用此方法将HashMap转换为String：
private String getPostDataString(HashMap<String, String> postDataParams) {
StringBuilder result = new StringBuilder();
boolean first = true;
for (Map.Entry<String,String> entry : postDataParams.entrySet()){
if(first){
first = false;
}else{
result.append(",");
}
result.append("\"");
result.append(entry.getKey());
result.append("\":\"");
result.append(entry.getValue());
result.append("\"");
}
return "{" + result.toString() + "}";
}