dct = {
"a": [1,3,5,4213,5345,644,236],
"b": [1,3,5,1264,2545,2432,75642,24354,432],
"c": [1,3,5,54542,354],
"d": [1,3,5,443,3564,21],
"e": [1,3,5,-2543,45421,-234],
"f": [1,3,5,4243,264,21356],
"g": [1,3,5,245643,2312,5768,35546]
}
现在,我想查找并返回所有键中包含的所有关节元素的列表,即[1,3,5]
set.intersection
:dict
。请参阅下面的带有答案的更正。 从集合导入defaultdict