Java JTree仅扩展一级节点

问题描述 投票:12回答:5

[使用JTree,假设根节点为0级,并且根下方最多可能有5个层,我如何轻松地扩展所有1级节点,以便所有1级和2级分支和叶子都可见,而3级和下面不是吗?

java swing jtree
5个回答
21
投票

感谢大家的快速反应。但是,现在我找到了我正在寻找的简单解决方案。由于某种原因,我只是在JavaDocs中看不到DefaultMutableTreeNode.getLevel()!仅供参考,我现在正在做的是:

    DefaultMutableTreeNode currentNode = treeTop.getNextNode();
    do {
       if (currentNode.getLevel()==1) 
            myTree.expandPath(new TreePath(currentNode.getPath()));
       currentNode = currentNode.getNextNode();
       }
    while (currentNode != null);

3
投票

您有一些Tree实用程序类可以精确地做到这一点:

this one

public class SimpleNavigatorTreeUtil {

   /**
    * Expands/Collapse specified tree to a certain level.
    * 
    * @param tree jtree to expand to a certain level
    * @param level the level of expansion
    */
   public static void expandOrCollapsToLevel(JTree tree, TreePath treePath,int level,boolean expand) {
      try {
         expandOrCollapsePath(tree,treePath,level,0,expand);
      }catch(Exception e) {
e.printStackTrace();
         //do nothing
      }
   }

   public static void expandOrCollapsePath (JTree tree,TreePath treePath,int level,int currentLevel,boolean expand) {
//      System.err.println("Exp level "+currentLevel+", exp="+expand);
      if (expand && level<=currentLevel && level>0) return;

      TreeNode treeNode = ( TreeNode ) treePath.getLastPathComponent();
      TreeModel treeModel=tree.getModel();
      if ( treeModel.getChildCount(treeNode) >= 0 ) {
         for ( int i = 0; i < treeModel.getChildCount(treeNode); i++  ) {
            TreeNode n = ( TreeNode )treeModel.getChild(treeNode, i);
            TreePath path = treePath.pathByAddingChild( n );
            expandOrCollapsePath(tree,path,level,currentLevel+1,expand);
         }
         if (!expand && currentLevel<level) return;
      }      
      if (expand) {
         tree.expandPath( treePath );
//         System.err.println("Path expanded at level "+currentLevel+"-"+treePath);
      } else {
         tree.collapsePath(treePath);
//         System.err.println("Path collapsed at level "+currentLevel+"-"+treePath);
      }
   }


}

基本上,您需要探索子节点,直到满足您的条件(此处是深度级别),然后展开所有节点,直到该点为止。


1
投票

由于您的1级节点都是根节点的所有子节点,并且假设您正在使用DefaultMutableTreeNode(需要调用getPath(),因此您可以像这样循环访问根节点的子节点:

Enumeration<?> topLevelNodes
    = ((TreeNode)tree.getModel().getRoot()).children();
while(topLevelNodes.hasMoreElements()) {
    DefaultMutableTreeNode node
        = (DefaultMutableTreeNode)topLevelNodes.nextElement();
    tree.expandPath(new TreePath(node.getPath()));
}

1
投票

以下内容适用于一级儿童。要扩展所有子代,请将.children()替换为.breadthFirstEnumeration()

import javax.swing.*;
import javax.swing.tree.*;
import java.awt.BorderLayout;
import java.awt.event.*;
import java.util.*;

public class Tree {
    public static void main(String[] args) {
        JPanel panel = new JPanel(new BorderLayout());
        final JTree tree = new JTree();
        panel.add(new JScrollPane(tree));
        JButton btn = new JButton("Press Me");
        btn.addActionListener(new ActionListener() {
            public void actionPerformed(ActionEvent ae) {
                for (Enumeration e = ((TreeNode)tree.getModel().getRoot()).children();e.hasMoreElements();) {
                    TreeNode tn = (TreeNode)e.nextElement();
                    tree.expandPath(new TreePath(((DefaultTreeModel)tree.getModel()).getPathToRoot(tn)));
                }
            }
        });
        panel.add(btn, BorderLayout.SOUTH);
        JFrame frame = new JFrame("");
        frame.getContentPane().add(panel);
        frame.setSize(300, 300);
        frame.setLocation(100, 100);
        frame.pack();
        frame.show();
    }
}

0
投票

对所有2级节点使用expand(TreePath)

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