Laravel 6重写FormRequest的failedValidation方法时,自定义验证错误'类不存在'

问题描述 投票:0回答:1

我在app\Http\Requests中创建了一个自定义验证类:

<?php

namespace App\Http\Requests;

use App\Http\Requests\BaseFormRequest;

class RegisterUserRequest extends BaseFormRequest
{
    protected static $NEEDS_AUTHORIZATION = false;

    protected static $FORM_RULES = [
        'first_name'              => 'required|string|max:80',
        'last_name'               => 'required|string|max:80',
        'email'                   => 'required|unique:users|email',
        'password'                => 'required|string|min:6|confirmed',
        'terms_conditions'        => 'accepted'
    ];

}

并在同一目录中扩展BaseFormRequest

<?php 

namespace App\Http\Requests;

use Illuminate\Foundation\Http\FormRequest;
use Illuminate\Validation\Validator;
use Illuminate\Validation\ValidationException;
use Illuminate\Http\Exceptions\HttpResponseException;
//use Illuminate\Http\Request;

abstract class BaseFormRequest extends FormRequest 
{
    protected static $NEEDS_AUTHORIZATION = true;
    protected static $FORM_RULES          = [];
    protected static $ERROR_MESSAGES      = [];

    /**
     * Determine if the user is authorized to make this request.
     *
     * @return bool
     */
    public function authorize() : bool
    {
        return !static::$NEEDS_AUTHORIZATION;
    }

    /**
     * Get the validation rules that apply to the request.
     *
     * @return array
     */
    public function rules() : array
    {
        return static::$FORM_RULES;
    }

    /**
     * Get the error messages for the defined validation rules.
     *
     * @return array
    */
    public function messages()
    {
        return static::$ERROR_MESSAGES;
    }


    /**
     * @overrride
     * Handle a failed validation attempt.
     *
     * @param  \Illuminate\Contracts\Validation\Validator  $validator
     * @return void
     *
     * @throws \Illuminate\Validation\ValidationException
     */
    protected function failedValidation(Validator $validator) : void
    {
        //throw (new ValidationException(response()->json($validator->errors(), 422)));
        throw new HttpResponseException(response()->json($validator->errors(), 422));
    }

}

现在,当尝试在我的控制器中使用它时:

<?php

namespace App\Http\Controllers\API;

use App\Services\UserService;
use Illuminate\Http\JsonResponse as JsonResponse;
//use Iluminate\Http\Request;
use App\Http\Requests\RegisterUserRequest;

class UserController extends Controller
{
    private $user;

    public function __construct(UserService $user)
    {
        $this->user = $user;
    }

    public function store(RegisterUserRequest $request) : JsonResponse
    {   
        $registered_user = $this->user->register($request->validated());

        return response()->json(['status' => 201, 'user_id' => $registered_user->id]);
    }

}

我遇到以下错误:

ReflectionException类App \ Http \ Requests \ RegisterUserRequest不存在

有趣的是,如果我删除了覆盖的方法failedValidation,该错误消失了,尽管它会将我重定向到主页,这是我要避免的错误。我想总是返回一个json响应。

有什么建议吗?谢谢

php laravel laravel-validation laravel-6 laravel-response
1个回答
0
投票

请注意,failedValidation()函数需要\Illuminate\Contracts\Validation\Validator的实例作为参数:

/**
* ...
* @param  \Illuminate\Contracts\Validation\Validator  $validator
* ...
*/ 

但是您要传递Illuminate\Validation\Validator实例:

use Illuminate\Validation\Validator; 

protected function failedValidation(Validator $validator) : void
{
    throw new HttpResponseException(response()->json($validator->errors(), 422));
}

因此,您可以更改

use Illuminate\Validation\Validator; 

to

use Illuminate\Contracts\Validation\Validator; 

或将其与参数中的名称空间一起传递:

protected function failedValidation(\Illuminate\Contracts\Validation\Validator $validator) : void
{
    throw new HttpResponseException(response()->json($validator->errors(), 422));
}
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