我有两张桌子:
select * from patient WHERE name = 'Dharam';
+----+--------+----------+---------------+-----+--------+
| id | name | townCity | contactnumber | age | gender |
+----+--------+----------+---------------+-----+--------+
| 5 | Dharam | sdfgsgfs | 252232 | 6 | Male |
| 6 | Dharam | sdfgsgfs | 252232 | 6 | Male |
| 12 | Dharam | sadasda | 213214124 | 2 | Female |
+----+--------+----------+---------------+-----+--------+
第二个表是相对的;
+----+------------+----------+--------------+
| id | patient_id | relation | relativeName |
+----+------------+----------+--------------+
| 5 | 5 | Son | Gyan |
+----+------------+----------+--------------+
| 6 | 6 | Son | Gyan |
+----+------------+----------+--------------+
| 12 | 12 | Wife | Suvidha |
+----+------------+----------+--------------+
我想得到一个相对名字的列表,其患者ID与使用peewee方法的亲属的id相匹配
我试图像这样创建一个连接:
select id, name from patient INNER JOIN relative ON
(patient.id == relative.id) WHERE patient.name = 'Dharam';
但是提出错误说:
MariaDB server version for the right syntax to use
near '= relative.id) WHERE patient.name = 'Dharam'' at line 1
我想出了这个:
query = (Relative.select(Relative.relativeName, Patient.id).join(Patient).where(Patient.id == Relative.id))
>>>
>>> for item in query: print item.relativeName
但它返回所有relativeNames而不是匹配id的那些。
弄清楚:
>>> query = (Relative.select(Relative.relativeName).join(Patient).where(Patient.name == 'Dharam'))
>>> for item in query: print item.relativeName