使用子弹和基于类的视图时找不到视图

Question

我的Django应用之一“ Pages”在models.py中具有许多不同的类。他们每个人都有自己的子弹属性/字段。我能够加载第一个URL-“公司”（头等舱），但由于某种原因无法加载其他URL。

我已经尝试过分别导入视图并为每个视图创建url路径。这样做时，只会加载最后一个URL（第三个URL）。

models.py

class Industry(models.Model):
    industry = models.CharField(max_length=140, null=True, blank=True, unique=True)
    slug = models.SlugField(max_length=40, null=True, blank=True)
    def __str__(self):
        return self.industry
    def save(self, *args, **kwargs):
        if not self.id:
            self.slug = slugify(self.industry)

            super(Industry, self).save(*args, **kwargs)

    def get_absolute_url(self):
        return reverse('industry_detail', args=[(self.slug)])

class Subindustry(models.Model):
    subindustry = models.CharField(max_length=140, null=True, blank=True, unique=True)
    industry = models.ForeignKey(
        Industry,
        on_delete=models.CASCADE,
        related_name='ParentIndustry',
    )
    slug = models.SlugField(max_length=40, null=True, blank=True)
    def __str__(self):
        return self.subindustry
    def save(self, *args, **kwargs):
        if not self.id:
            self.slug = slugify(self.subindustry)

            super(Subindustry, self).save(*args, **kwargs)

    def get_absolute_url(self):
        return reverse('subindustry_detail', args=[(self.slug)])



class Company(models.Model):
    name = models.CharField(max_length=50, blank=False, unique=True, default=(str(id)))
    website = models.URLField(max_length=100)
    ...
    slug = models.SlugField(max_length=40, null=True, blank=True)
    def __str__(self):
        return self.name
    def save(self, *args, **kwargs):
        if not self.id:
            self.slug = slugify(self.name)

            super(Company, self).save(*args, **kwargs)

    def get_absolute_url(self):
        return reverse('company_detail', args=[(self.slug)])

views.py

from django.views.generic import DetailView
from django.urls import reverse_lazy

# Create your views here.
from .models import Company, Industry, Subindustry

class CompanyDetailView(DetailView):
    model = Company
    template_name = 'company_detail.html'
    slug_field = 'slug'

class IndustryDetailView(DetailView):
    model = Industry
    slug_field = 'slug'
    template_name = 'industry_detail.html'


class SubindustryDetailView(DetailView):
    model = Subindustry
    slug_field = 'slug'
    template_name = 'subindustry_detail.html'

urls.py（Pages应用）

from django.urls import path

from .views import CompanyDetailView, IndustryDetailView, SubindustryDetailView

urlpatterns = [
     path('<slug:slug>/', CompanyDetailView.as_view(), name='company_detail'),
     path('<slug:slug>/', IndustryDetailView.as_view(), name='industry_detail'),
     path('<slug:slug>/', SubindustryDetailView.as_view(), name='subindustry_detail'),
]

urls.py（项目级别）

from django.contrib import admin
from django.urls import path, include
from django.views.generic.base import TemplateView


urlpatterns = [
    path('admin/', admin.site.urls),
    path('users/', include('users.urls')),
    path('users/', include('django.contrib.auth.urls')),
    path(r'aoa/', include('qa.urls')),
    path('business/', include('pages.urls')),
    path('', TemplateView.as_view(template_name='home.html'), name='home'),
]

预期：输入正确的URL时看到页面。例如。如果我尝试加载http://127.0.0.1:8000/business/construction/，它将加载（例如，这是一个行业值）。目前，只有公司价值加载，例如http://127.0.0.1:8000/business/macrodepot/请注意，我确实有每个类的HTML模板，并且如果views.py文件中只有一个HTML模板，则可以看到它们。

实际：当我输入一个行业或子行业的URL时，将收到以下404。好像只在companydetailview中寻找子弹。

找不到页面（404）请求方法：GET要求网址：http://127.0.0.1:8000/business/construction/提出者：pages.views.CompanyDetailView找不到与查询匹配的公司

Answer 1

这是因为django按照它们在urlpatterns中的放置顺序来评估这些url。它接收到对企业/建筑的请求，并调用CompanyDetailView，它返回404。您需要为每个模型使用不同的网址格式：

    urlpatterns = [
     path('company/<slug:slug>/', CompanyDetailView.as_view(), name='company_detail'),
     path('industry/<slug:slug>/', IndustryDetailView.as_view(), name='industry_detail'),
     path('subindustry/<slug:slug>/', SubindustryDetailView.as_view(), name='subindustry_detail'),
]