如何从Android设备获取主机名

问题描述 投票:0回答:3

我正在实现一种获取 Android 设备主机名的方法。我为此使用 InetAddress 类。但是,我遇到了致命的异常。方法如下。我添加了一个 try/catch 块,但仍然不起作用。任何帮助表示赞赏。编辑并添加异常错误

/**
     * getHostname returns the hostname of android device as string
     *
     * @param context
     * @return hostname
     */

    public String getHostname(Context context) {
        String hostName;
        try {
            InetAddress netHost = InetAddress.getLocalHost();
            hostName = netHost.getHostName();
        } catch (UnknownHostException ex) {
            hostName = null;
        }

        return hostName;
    }

致命异常

E/AndroidRuntime: FATAL EXCEPTION: main
                  Process: com.example.george.droidnet, PID: 23439
                  java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.george.droidnet/com.example.george.droidnet.TcpConfigActivity}: android.os.NetworkOnMainThreadException
                      at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2416)
                      at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2476)
                      at android.app.ActivityThread.-wrap11(ActivityThread.java)
                      at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1344)
                      at android.os.Handler.dispatchMessage(Handler.java:102)
                      at android.os.Looper.loop(Looper.java:148)
                      at android.app.ActivityThread.main(ActivityThread.java:5417)
                      at java.lang.reflect.Method.invoke(Native Method)
                      at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:726)
                      at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:616)
                   Caused by: android.os.NetworkOnMainThreadException
                      at android.os.StrictMode$AndroidBlockGuardPolicy.onNetwork(StrictMode.java:1273)
                      at java.net.InetAddress.lookupHostByName(InetAddress.java:431)
                      at java.net.InetAddress.getLocalHost(InetAddress.java:409)
                      at com.example.george.droidnet.TcpConfigActivity.getHostname(TcpConfigActivity.java:100)
                      at com.example.george.droidnet.TcpConfigActivity.onCreate(TcpConfigActivity.java:40)
                      at android.app.Activity.performCreate(Activity.java:6237)
                      at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1107)
                      at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2369)
                      at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2476) 
                      at android.app.ActivityThread.-wrap11(ActivityThread.java) 
                      at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1344) 
                      at android.os.Handler.dispatchMessage(Handler.java:102) 
                      at android.os.Looper.loop(Looper.java:148) 
                      at android.app.ActivityThread.main(ActivityThread.java:5417) 
                      at java.lang.reflect.Method.invoke(Native Method) 
                      at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:726) 
                      at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:616) 
android android-studio hostname inetaddress
3个回答
1
投票

伙计,在 Java 中你不能在主线程上“做网络事情”。为此,您必须将其放入 AsyncTask 中,如下所示:

public String getHostName() {
    AsyncTack<Void, Void, String> task = new AsyncTask<Void, Void, String>() {
        @Override
        protected Void doInBackground(Void... voids) {
            String hostName;
            try {
                InetAddress netHost = InetAddress.getLocalHost();
                hostName = netHost.getHostName();
            } catch (UnknownHostException ex) {
                hostName = null;
            }

            return hostName;
        }
    };

    task.execute();
    try {
        return task.get();
    } catch (Exception e) {
        return null;
    }
}

这段代码应该可以工作。


0
投票
Caused by: android.os.NetworkOnMainThreadException

使用另一个线程进行联网。 AsyncTask 可能会帮助你。


0
投票

AsyncTask 在 API 30 中已弃用

这是一个 kotlin 解决方案:

            StrictMode.setThreadPolicy(StrictMode.ThreadPolicy.Builder().permitAll().build())
            val t = Thread() {
                val x = InetAddress.getLocalHost()
                println (x)
            }.run()

请注意,您还需要设置 ThreadPolicy 才能运行此代码。

这段代码有效,但它确实没有解决发布问题的意图,因为使用此方法获得的主机名是“localhost”。

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