在Alamofire设置超时

问题描述 投票:30回答:11

我正在使用Alamofire 4.0.1,我想为我的请求设置超时。我试过这个question给出的解决方案:

在第一种情况下,它会抛出NSURLErrorDomain(正确设置超时):

let configuration = URLSessionConfiguration.default
configuration.timeoutIntervalForRequest = 10

    let sessionManager = Alamofire.SessionManager(configuration: configuration)
    sessionManager.request("yourUrl", method: .post, parameters: ["parameterKey": "value"])
            .responseJSON {
                response in
                switch (response.result) {
                case .success:
                    //do json stuff
                    break
                case .failure(let error):
                    if error._code == NSURLErrorTimedOut {
                        //timeout here
                    }
                    print("\n\nAuth request failed with error:\n \(error)")
                    break
                }
            }

在第二种情况下,超时不会被替换,仍然设置为60秒。

let manager = Alamofire.SessionManager.default
manager.session.configuration.timeoutIntervalForRequest = 10

manager.request("yourUrl", method: .post, parameters: ["parameterKey": "value"])

我在ios 10.1中运行

我的代码:(它不起作用)

    let configuration = URLSessionConfiguration.default
    configuration.timeoutIntervalForRequest = 10 // seconds
    configuration.timeoutIntervalForResource = 10
    let alamoFireManager = Alamofire.SessionManager(configuration: configuration)

    alamoFireManager.request("my_url", method: .post, parameters: parameters).responseJSON { response in


        switch (response.result) {
        case .success:
                 //Success....
            break
        case .failure(let error):
            // failure...
            break
        }
    }

解决了Alamofire github线程:Alamofire 4.3.0 setting timeout throws NSURLErrorDomain error #1931

ios swift alamofire
11个回答
25
投票

请试试这个: -

    let request = NSMutableURLRequest(url: URL(string: "")!)
    request.httpMethod = "POST"
    request.setValue("application/json", forHTTPHeaderField: "Content-Type")
    request.timeoutInterval = 10 // 10 secs
    let values = ["key": "value"]
    request.httpBody = try! JSONSerialization.data(withJSONObject: values, options: [])
    Alamofire.request(request as! URLRequestConvertible).responseJSON {
        response in
        // do whatever you want here
    }

0
投票

如果您不想自己构建UrlRequest,您仍然可以使用Alamofire来构建它。

    // set this flag to false so the request will not be sent until
    // resume() is called
    sessionManager.startRequestsImmediately = false

    var urlRequest = sessionManager.request(url,
                                            method: method,
                                            parameters: params,
                                            encoding: encoding,
                                            headers: allHeaders).request!

    urlRequest.timeoutInterval = 10

    let request = sessionManager.request(urlRequest).responseJSON { (result) in
        // use the result
    }

    // need to start the request
    request.resume()

-1
投票

以上都不适合我:我在swift 4.2 Alamofire 4.5

我成功解决了这个问题:

let request = Alamofire.request("routee", method: .post, parameters: data, encoding: JSONEncoding.default, headers: getHeaders())

/// getting request created by Alamofire and then updating its timeout Value

let url = URL(string: "myroute")!
        var request = try URLRequest(url: url, method: method, headers: headers)
        request.timeoutInterval = 900 // timeout
        request = try JSONEncoding.default.encode(request, with: data)

Alamofire.request(request)
    .responseJSON { response in

}

17
投票

我也有同样的问题,我想我找到了解决方案。尝试在函数外部的类SessionManager?中声明alamofireManageror

class ViewController: UIViewController {
   var alamoFireManager : SessionManager? // this line

   func alamofire(){
        let configuration = URLSessionConfiguration.default
        configuration.timeoutIntervalForRequest = 10
        configuration.timeoutIntervalForResource = 10
        alamoFireManager = Alamofire.SessionManager(configuration: configuration) // not in this line

        alamoFireManager.request("my_url", method: .post, parameters: parameters).responseJSON { response in


        switch (response.result) {
        case .success:
                 //Success....
            break
        case .failure(let error):
               // failure...
             break
       }
     }
   }

}

11
投票

试试这个:

    let configuration = NSURLSessionConfiguration.defaultSessionConfiguration()
    configuration.timeoutIntervalForRequest = 4 // seconds
    configuration.timeoutIntervalForResource = 4
    self.alamoFireManager = Alamofire.Manager(configuration: configuration)

Swift 3.0

    let configuration = URLSessionConfiguration.default
    configuration.timeoutIntervalForRequest = 4 // seconds
    configuration.timeoutIntervalForResource = 4
    self.alamoFireManager = Alamofire.SessionManager(configuration: configuration)

8
投票

正如马特所说,问题如下

这里的区别在于初始化的管理器不是拥有的,并且在它超出范围后不久就会被释放。因此,任何待处理的任务都将被取消。

这个问题的解决方案是由rainypixels编写的

import Foundation导入Alamofire

class NetworkManager {

    var manager: Manager?

    init() {
        let configuration = NSURLSessionConfiguration.defaultSessionConfiguration()
        manager = Alamofire.Manager(configuration: configuration)
    }
}

而我自己的版本

class APIManager {

    private var sessionManager = Alamofire.SessionManager()

    func requestCards(_ days_range: Int, success: ((_ cards: [CardModel]) -> Void)?, fail: ((_ error: Error) -> Void)?) {
        DispatchQueue.global(qos: .background).async {
            let parameters = ["example" : 1]

            let headers = ["AUTH" : "Example"]

            let configuration = URLSessionConfiguration.default
            configuration.timeoutIntervalForRequest = 10
            self.sessionManager = Alamofire.SessionManager(configuration: configuration)

            self.sessionManager.request(URLs.cards.value, method: .get, parameters: parameters, encoding: URLEncoding.default, headers: headers).responseJSON { (response) in
                switch response.result {
                case .success:
                    //do json stuff
                    guard let json = response.result.value as? [String : Any] else { return }
                    guard let result = json["result"] as? [[String : Any]] else { return }
                    let cards = Mapper<CardModel>().mapArray(JSONArray: result)
                    debugPrint("cards", cards.count)
                    success?(cards)
                case .failure(let error):
                    if error._code == NSURLErrorTimedOut {
                        //timeout here
                        debugPrint("timeOut")
                    }
                    debugPrint("\n\ncard request failed with error:\n \(error)")
                    fail?(error)
                }
            }
        }
    }
}

也可以为它做一个经理

import Alamofire

struct AlamofireAppManager {

    static let shared: SessionManager = {
        let configuration = URLSessionConfiguration.default
        configuration.timeoutIntervalForRequest = 10
        let sessionManager = Alamofire.SessionManager(configuration: configuration)
        return sessionManager
    }()

}

6
投票

基于@ kamal-thakur的回复。

斯威夫特3:

var request = URLRequest(url: NSURL.init(string: "YOUR_URL") as! URL)
request.httpMethod = "POST"
request.setValue("application/json", forHTTPHeaderField: "Content-Type")
request.timeoutInterval = 10 // 10 secs
let postString = "param1=\(var1)&param2=\(var2)"
request.httpBody = postString.data(using: .utf8)
Alamofire.request(request).responseJSON {
    response in
    // do whatever you want here
}

6
投票

如果你使用的是Alamofire的一个实例,你可以像这样制作一个懒惰的var:

   private lazy var alamoFireManager: SessionManager? = {
    let configuration = URLSessionConfiguration.default
    configuration.timeoutIntervalForRequest = 5
    configuration.timeoutIntervalForResource = 5
    let alamoFireManager = Alamofire.SessionManager(configuration: configuration)
    return alamoFireManager

}()

适用于Swift 4.2


2
投票

经过大量的尝试,我用下一个做到了:

var timeout = 300 // 5 minutes

//Post values
    let parameters:Parameters = parameters

    //Server value
    let url:URL = (url)


    //Make the request
    let configuration = URLSessionConfiguration.default
    configuration.timeoutIntervalForResource = TimeInterval(timeout)
    configuration.timeoutIntervalForRequest = TimeInterval(timeout)

    let sessionManager = Alamofire.SessionManager(configuration: configuration)

     sessionManager.request(url,parameters:parameters).validate(statusCode: 200..<300).responseJSON { response in


        print(response.request)  // original URL request
        print(response.response) // URL response

        print(sessionManager.session.configuration.timeoutIntervalForRequest)   // result of response time
        print(response.timeline.totalDuration)


        switch response.result {
        case .success:

            if let valJSON = response.result.value {


               //use your json result 



            }

        case .failure (let error):

            print("\n\nAuth request failed with error:\n \(error)")

        }
    }

我希望它有所帮助;)


0
投票

我有swift的代码2.3希望它可以帮助你,尝试一下

    let configuration = NSURLSessionConfiguration.defaultSessionConfiguration()
    configuration.timeoutIntervalForResource = 10800 // seconds
    configuration.timeoutIntervalForRequest = 10800 // seconds

    alamoFireManager = Alamofire.Manager(configuration: configuration)

0
投票

它对我有用:

let url:String = "http://..."
let request = URLRequest(url: url)
request.httpMethod = "POST"
request.setValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("Kirk Hamet", forHTTPHeaderField:"name")
request.timeoutInterval = 23 //Second

Alamofire.request(request).responseJSON {
                response in
    if response.result.isSuccess == true {

    }else{

    }

}

Swift 4.1

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