我试图用ESP8266测试请求，我希望请求使用HTTPS，但请求结果总是400个坏请求，那么是什么原因导致我写的代码错误？
#include <ESP8266WiFi.h>
#include <WiFiClientSecure.h>
#ifndef STASSID
#define STASSID "xxxxxxx"
#define STAPSK "xxxxxxxxx"
#endif
const char* ssid = "xxxxx";
const char* password = "xxxxxxxx";
const char* host = "webhook.site";
const int httpsPort = 443;
const char fingerprint[] PROGMEM = "09:F6:00:C3:67:B0:80:14:34:E3:08:D7:4A:64:20:85:83:F4:80:A1";
void setup() {
Serial.begin(115200);
Serial.println();
Serial.print("connecting to ");
Serial.println(ssid);
WiFi.mode(WIFI_STA);
WiFi.begin(ssid, password);
while (WiFi.status() != WL_CONNECTED) {
delay(500);
Serial.print(".");
}
Serial.println("");
Serial.println("WiFi connected");
Serial.println("IP address: ");
Serial.println(WiFi.localIP());
// Use WiFiClientSecure class to create TLS connection
WiFiClientSecure client;
Serial.print("connecting to ");
Serial.println(host);
Serial.printf("Using fingerprint '%s'\n", fingerprint);
client.setFingerprint(fingerprint);
if (!client.connect(host, httpsPort)) {
Serial.println("connection failed");
return;
}
delay(500);
if (client.verify(fingerprint, host)) {
Serial.println("certificate matches");
} else {
Serial.println("certificate doesn't match");
}
delay(500);
String url = "/4cf42a06-5df4-4459-b8f3-5d29f1ed319d";
Serial.print("requesting URL: ");
Serial.println(url);
String request = String("GET ") + url + " HTTP/1.0 \r\n" +
"Host: " + host + "\r\n" +
"Accept: *" + "/" + "*\r\n" +
"User-Agent: BuilderFailureDetectorESP8266\r\n" +
"Connection: close\r\n\r\n";
Serial.println(request);
client.print(request);
Serial.println("request sent");
int waitcount = 0;
while (!client.available() && waitcount++ ) {
delay(10);
}
while(client.available()){
String line = client.readStringUntil('\r');
Serial.print(line);
}
while (client.connected()) {
String line = client.readStringUntil('\r');
Serial.println("headers received"+line);
if (line == "\r") {
Serial.println("headers received"+line);
break;
}
}
}
void loop() {
}
以下是上述程序的输出
connecting to xxxx
.....
WiFi connected
IP address:
192.168.1.13
connecting to webhook.site
Using fingerprint '09:F6:00:C3:67:B0:80:14:34:E3:08:D7:4A:64:20:85:83:F4:80:A1'
certificate matches
requesting URL: /4cf42a06-5df4-4459-b8f3-5d29f1ed319d
GET /4cf42a06-5df4-4459-b8f3-5d29f1ed319d HTTP/1.0
Host: webhook.site
Accept: */*
User-Agent: BuilderFailureDetectorESP8266
Connection: close
request sent
HTTP/1.0 400 Bad request
Cache-Control: no-cache
Connection: close
Content-Type: text/html
<html><body><h1>400 Bad request</h1>
Your browser sent an invalid request.
</body></html>
我的代码有问题吗？每个人都可以帮助我吗??? ...我正在寻找Google上几个帖子中的以下示例
关于空白，HTTP可能非常苛刻。在你的行
String request = String("GET ") + url + " HTTP/1.0 \r\n" +
在HTTP/1.0之后有一个不必要的空间。删除空格，您应该通过“400 Bad request”响应。
String request = String("GET ") + url + " HTTP/1.0\r\n" +