从过去7天没有联系人的客户中选择ID，在该月中选择2次

Question

我有2个表：customer，c_contact。 c_contact是我发给客户的所有电子邮件。从现在开始，我需要制定一条新规则，即客户在以下情况下无法收到新电子邮件：1）在过去7天内收到了一封电子邮件2）当前发送了2封或者以上的电子邮件月

我想是这样的：

SELECT * from customer c inner join c_contact cc on cc.ID = c.ID WHERE
ID not in (select ID from c_contact c1 where c1.ID = cc.ID and 
c1.CONTDATE >= getdate()-7) AND
ID not in (select count(ID) from c_contact where MONTH(contdate) = MONTH(getdate()) 
and YEAR(contdate) = YEAR(getdate() HAVING count(ID) >= 2)

但表c_contact是巨大的，运行它需要很长时间。有没有办法在1“ID不在”中执行这两个条件？我认为它会运行得更快。

Answer 1

我不确定这对性能有多好，但是我可以做到这一点。

SELECT  *
FROM    customer c
        OUTER APPLY (SELECT COUNT(*) monthCount 
                     FROM   c_contact cc 
                     WHERE  cc.ID = c.ID 
                            AND cc.contdate >= DATEADD(mm, DATEDIFF(mm, 0, GETDATE()), 0) 
                            AND cc.contdate < DATEADD(mm, DATEDIFF(mm, 0, GETDATE()) + 1, 0)) ct
        OUTER APPLY (SELECT MAX(cc.contdate) lastSent 
                     FROM   c_contact cc 
                     WHERE  cc.ID = c.ID AND cc.contdate < GETDATE()) ls
WHERE   ct.monthCount < 2
        AND ls.lastSent < DATEADD(dd, -7, GETDATE()) 

或者，使用左连接而不是2外部适用，您可以尝试：

SELECT  *
FROM    customer c
        LEFT JOIN (
            SELECT  cc.ID, 
                    COUNT(CASE WHEN MONTH(cc.contdate) = MONTH(GETDATE()) THEN 1 END) monthCount,
                    MAX(cc.contdate) lastSent
            FROM    c_contact cc
            WHERE   cc.contdate BETWEEN DATEADD(dd, -32, GETDATE()) AND GETDATE()
            GROUP BY cc.ID
        ) cc ON c.ID = cc.ID
WHERE   ISNULL(cc.monthCount,0) < 2
        AND ISNULL(cc.lastSent,GETDATE()) < DATEADD(dd, -7, GETDATE()) 

如果你真的只想使用NOT IN，你可以尝试：

SELECT  *
FROM    customer c
WHERE   c.ID NOT IN (
            SELECT  cc.ID, 
                    COUNT(CASE WHEN MONTH(cc.contdate) = MONTH(GETDATE()) THEN 1 END) monthCount,
                    MAX(cc.contdate) lastSent
            FROM    c_contact cc
            WHERE   cc.contdate BETWEEN DATEADD(dd, -32, GETDATE()) AND GETDATE()
            GROUP BY cc.ID
            HAVING  COUNT(CASE WHEN MONTH(cc.contdate) = MONTH(GETDATE()) THEN 1 END) > 1
                    AND MAX(cc.contdate) >  DATEADD(dd, -7, GETDATE()) 
        )

Answer 2

这也可以通过其他方式完成：

select A.* from Customers A
where A.CustID not in (
select B.CustID from (
(select C.CustID, Count(C.CustID) cnt from Contacts C
where C.ContactedDate >=GETDATE()-7 group by C.CustID)
UNION
(select C.CustID, Count(C.CustID) cnt from Contacts C
where C.ContactedDate <=GETDATE()-7 and Month(C.ContactedDate) = Month(GETDATE()) and YEAR(C.ContactedDate)= YEAR(GETDATE()) 
group by C.CustID having COUNT(C.CustID) >= 2)) B);
go

将客户ID分为两组 - 第一组包含最近7天内联系的ID，第二组包含当前最后三周联系的ID。在选择所需的客户组时，最后排除这两组中的UNION。