我正在尝试将复杂数组的每个元素乘以一个乘数,以进行傅立叶变换。我正在将汉宁窗口过滤器应用于wave函数的复杂文件。
我正在使用CodeBlocks在C ++中工作,我一直得到->
error: invalid types 'double[int]' for array subscript
我的代码在这里:
#include <iostream>
#include <fstream>
#include <string>
#include <regex>
#include <cmath>
#define PI 3.14159265359
using namespace std;
class Complex {
public:
Complex();
Complex(double realNum);
Complex(double realNum, double imagNum);
//Complex(double real = 0.0, double imaginary = 0.0); This avoids the 3 above?
Complex(const Complex& obj);
private:
double real;
double imaginary;
};
Complex::Complex(const Complex& obj) {
real = obj.real;
imaginary = obj.imaginary;
}
Complex::Complex () {
real = 0;
imaginary = 0;
}
Complex::Complex (double realNum) {
real = realNum;
imaginary = 0;
}
Complex::Complex (double realNum, double imagNum) {
real = realNum;
imaginary = imagNum;
}
int main () {
Complex *complexArray = new Complex[1000];
ifstream myfile("myfile.txt");
/* this will match the complex numbers of the form - 123.123 + 14.1244 or 123 - 1343.193 and so on,
basically assumes that both the real and the imaginary parts are both doubles*/
regex reg_obj("^[ ]*([-]?\\d+(\\.\\d+)?)\\s*([+-])\\s*(\\d+(\\.\\d+)?)i");
smatch sm;
string line;
int i = 0;
double real, imag;
if (myfile.is_open()) {
while (! myfile.eof()) {
getline(myfile, line);
if(regex_search(line, sm, reg_obj)){
real = stod(sm[1]); // this ([-]?\\d+(\\.\\d+)?) is group 1 and will match the real part of the number
imag = stod(sm[4]); // second group (\\d+(\\.\\d+)?)i is group 4 which matches the imaginary part of the complex number without matching + or - which are taken care of separately because there could be space between the +|- symbol and the imaginary part
if(sm[3]=="-") imag = -imag;
complexArray[i] = Complex(real, imag);
i++;
}
// Hanning Window
for (int i = 0; i < 1000; i++) {
double multiplier = 0.5 * (1 - cos(2*PI*i/999));
complexArray[i] = multiplier[i] * complexArray[i];
}
}
myfile.close();
}else {
cout << "Error. Could not find/open file." ;
}
cout << complexArray << endl;
return 0;
};
我想将复杂对象的每个元素乘以乘法数组中的每个元素。我不确定执行此操作的正确方法。
对于此循环中的初学者
for (int i = 0; i < 1000; i++) {
double multiplier = 0.5 * (1 - cos(2*PI*i/999));
complexArray[i] = multiplier[i] * complexArray[i];
}
变量multiplier
被声明为double类型的标量对象。所以你需要写
complexArray[i] = multiplier * complexArray[i];
代替
complexArray[i] = multiplier[i] * complexArray[i];
此外,您还需要为您的课程重载operator *
。
例如
class Complex {
public:
Complex();
Complex(double realNum);
Complex(double realNum, double imagNum);
//Complex(double real = 0.0, double imaginary = 0.0); This avoids the 3 above?
Complex(const Complex& obj);
friend const Complex operator *( double, const Complex & );
private:
double real;
double imaginary;
};
//...
const Complex operator *( double value, const Complex &c )
{
return { value * c.real, value * c.imaginary };
}
也是while循环中的条件
while (! myfile.eof()) {
getline(myfile, line);
//...
替代
while ( getline(myfile, line) ) {
//...