如何从多个选定的行中获取数据并显示在另一个VC tableview单元格Swift4中

问题描述 投票:0回答:2

你好我试图完成我的任务,因为2天但仍然没有成功搜索到处,我想从tableview单元格中选择多行(包含2个标签和一个图像)然后我想转移到另一个vc并在tableview中显示,我能够选择多行并从选定的行中获取此类型索引,但现在我不知道如何获取数据并转移到另一个vc并在表视图中显示请帮助我获取选择的行索引,如此[[0,1] ],[0,2],[0,3]

VS代码

class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource {


    @IBOutlet weak var tableview: UITableView!


    var labone = ["1","2","3","4","5","6"]
    var labtwo = ["a","b","c","d","e","f"]
    var img =  ["bag","bag","bag","bag","bag","bag"]


    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }

    @IBAction func button(_ sender: Any) {

        let selectedindexPath = tableview.indexPathsForSelectedRows
        if(selectedindexPath != nil){
            let toy  = labone[0]
            print(toy)
            print(selectedindexPath) }

        else{
            print("null")
        }
    }

    func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {

        return labone.count
    }

    func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
         let cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath)

         let name = cell.viewWithTag(1) as! UILabel
        let name_two = cell.viewWithTag(2) as! UILabel
        let imgg = cell.viewWithTag(3) as! UIImageView

        name.text = labone[indexPath.row]
        name_two.text = labtwo[indexPath.row]
        imgg.image = UIImage(named: img[indexPath.row])


        return cell

    }
    func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
        let cell = tableView.dequeueReusableCell(withIdentifier: "cell",for: indexPath)
        cell.contentView.backgroundColor = UIColor.yellow

    }


    func tableView(_ tableView: UITableView, didDeselectRowAt indexPath: IndexPath) {
      let cell = tableView.dequeueReusableCell(withIdentifier: "cell")
        // let selectedCell = tableview.cellForRow(at: indexPath)
        if let label = cell?.contentView.viewWithTag(4) as? UIImageView {
            label.image = UIImage(named: "check_disable")
        }

    }

}
ios swift tableview cell
2个回答
0
投票

您应该使用如下所示的结构,然后更新所选项目或取消选择的项目状态,然后当您想要转到下一个viewController时,您可以使用下面选择的项目过滤dataSource,

 class CellModel {

    var labelOne: String
    var labelTwo: String
    var imageName: String
    var isSelected = false

    init(_ labelOne: String, labelTwo: String, imageName: String) {
        self.labelOne = labelOne
        self.labelTwo = labelTwo
        self.imageName = imageName
    }
}

更新你的viewController,

class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource {

   let dataSource = [CellModel("1", labelTwo: "a", imageName: "bag"),
                     CellModel("2", labelTwo: "b", imageName: "bag"),
                     CellModel("3", labelTwo: "c", imageName: "bag"),
                     CellModel("4", labelTwo: "d", imageName: "bag"),
                     CellModel("5", labelTwo: "e", imageName: "bag"),
                     CellModel("6", labelTwo: "f", imageName: "bag")]
}

然后你可以更新你的cellForRowAt,如下所示,

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
         let cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath)

       let name = cell.viewWithTag(1) as! UILabel
       let name_two = cell.viewWithTag(2) as! UILabel
       let imgg = cell.viewWithTag(3) as! UIImageView

       let model = self.dataSource[indexPath.row]
       name.text = model.labelOne
       name_two.text = model.labelTwo
       imgg.image = UIImage(named: model.imageName)

       return cell
    }

用这个更新numberOfRowInSection

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {    
     return self.dataSource.count
 }

并且你可以像这样选择/取消选择单元格时更新模型的状态,

func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
        let cell = tableView.dequeueReusableCell(withIdentifier: "cell",for: indexPath)
        cell.contentView.backgroundColor = UIColor.yellow
        self.dataSource[indexPath.row].isSelected = true
    }


    func tableView(_ tableView: UITableView, didDeselectRowAt indexPath: IndexPath) {
      let cell = tableView.dequeueReusableCell(withIdentifier: "cell")
        // let selectedCell = tableview.cellForRow(at: indexPath)
        if let label = cell?.contentView.viewWithTag(4) as? UIImageView {
            label.image = UIImage(named: "check_disable")
            self.dataSource[indexPath.row].isSelected = false
      }
 }

最后在按钮操作中,您可以过滤所选模型并传递给下一个viewController

@IBAction func button(_ sender: Any) {

     let selectedItems = self.dataSource.filter({ $0.isSelected == true })
     // Pass to next ViewController the selectedItmes
}

0
投票

正如@Rakshith在他们的评论中所建议的那样,将您的数据(labone,labtwo,img数组)移出视图控制器并移动到模型对象中。将该模型对象传递给第二个视图控制器。

还要在第二个视图控制器中创建一个数组selectedIndexPaths。当您点击ViewController中的按钮时,获取所选索引路径的数组并将其传递给第二个视图控制器。

在第二个视图控制器的viewWillAppear中,使用selectedIndexPaths变量将所选项目复制到数组itemsToDisplay中,并在表视图数据源方法中使用它来填充第二个视图控制器的表视图。

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