使用 SAS 中的新变量将宽转为长

Question

我有一个数据集，其中包含个人列表以及他们是否参与某个项目多年。

身份证	kl2_2016	kl2_2017
琼斯	1	0
b史密斯	0	1

...等等

我希望它看起来像这样

观察	年	总服务
1	2016	20
2	2017	71

我正在使用此代码

proc sql;
    create table year_service as
    select
    distinct 
            sum(kl2_2016) as kl2_2016,
            sum(kl2_2017) as kl2_2017,
            sum(kl2_2018) as kl2_2018,
            sum(kl2_2019) as kl2_2019,
            sum(kl2_2020) as kl2_2020,
            sum(kl2_2021) as kl2_2021,
            sum(kl2_2022) as kl2_2022,
            sum(kl2_2023) as kl2_2023,
            sum(kl2_2024) as kl2_2024,
            sum(kl2_2025) as kl2_2025
            from have
;
quit;

proc transpose data=year_service 
   out=year_service_long;
   var kl2_2016-kl2_2025;
   
run;

但这不是我想要的。有人可以帮助我吗？

Answer 1

让

PROC TRANSPOSE

为您处理列要容易得多，这将更优雅地处理输入数据中的更改。我会像这样处理它：

/* Example input. */
data have;
   ID = "ajones"; kl2_2016 = 1; kl2_2017 = 0; output;
   ID = "bsmith"; kl2_2016 = 0; kl2_2017 = 1; output;
run;

proc sort data=have; by id; run;

/* Put the different years (values of KL2_:) on separate records. */
proc transpose data=have out=long;
   by id;
   var kl2_:;
run;

/* Summarize in whatever way you want. */
proc sql;
   create table want as
      select distinct input(scan(_name_, 2, "_"), best.) as year,
                      sum(col1) as total_service from long group by 1;
quit;