使用Swift 3错误'缺少所需的参数:grant_type'

问题描述 投票:0回答:1

我正在使用Twitter API,我想获取access_Token,但出现此错误:

{
"errors" : [
  {
    "message" : "Missing required parameter: grant_type",
    "label" : "forbidden_missing_parameter",
    "code" : 170
  }
 ]
}. 

我的要求如下:

let dict = ["grant_type" : "client_credentials"]  

requestPOSTURL("https://api.twitter.com/oauth2/token", params: dict as [String : AnyObject] , headers: ["Authorization" : "Basic " + strHeader, "Content-Type" : "application/x-www-form-urlencoded;charset=UTF-8"], success: { (json) in

        Helper.sharedInstance.Print(json as AnyObject)

    }, failure: {(error) in

        Helper.sharedInstance.Print(error as AnyObject)
    }). 

func requestPOSTURL(_ strURL : String, params : [String : AnyObject]?, headers : [String : String]?, success:@escaping (JSON) -> Void, failure:@escaping (Error) -> Void){
    sessionManager.request(strURL, method: .post, parameters: params, encoding: JSONEncoding.default, headers: headers).responseJSON { (responseObject) -> Void in
        //print(responseObject)
        if responseObject.result.isSuccess {
            let resJson = JSON(responseObject.result.value!)
            success(resJson)
        }
        if responseObject.result.isFailure {
            let error : Error = responseObject.result.error!
            failure(error)
        }
    }
}

这里,我试图获取access_Token(OAuth),但由于上述错误即将到来而无法获取。

ios twitter swift3
1个回答
0
投票

我已经遇到了类似的问题,并且使用本机NSMutableURLRequest进行了修复。https://stackoverflow.com/a/59472862/1528061

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