合并两个数组并删除两个重复项（如果出现）

Question

我有两个数组想要组合，然后在出现重复项时消除这两个值。我怎样才能实现这个目标？

arr1 = [1,2,3,4,5,6,7]

arr2 = [3,5,6,7]

我想留下 arr3 = [1,2,4]

谢谢

Answer 1

可以使用filter方法只保留那些不重复的元素。如果某个元素在组合数组中出现多次，则该元素被视为重复。

const arr1 = [1, 2, 3, 4, 5, 6, 7];
const arr2 = [3, 5, 6, 7];

const combinedArray = arr1.concat(arr2);

const resultArray = combinedArray.filter(item => {
    // Count the occurrence of the current item in the combined array
    const occurrence = combinedArray.filter(x => x === item).length;

    // Keep the item only if its occurrence is exactly 1
    return occurrence === 1;
});

console.log(resultArray); // Output: [1, 2, 4]