使用tkinter将文件路径保存在变量中

Question

我正在使用tkinter来为我拥有的旧脚本创建GUI，但是我现在陷入困境。我想单击一个按钮以打开“搜索文件”窗口，选择一个特定文件并将其路径保存在变量中。我拥有的代码能够打开窗口，然后可以选择文件并显示其路径，但是我找不到将这种路径保存在变量中的方法。这就是我所拥有的：

from tkinter import *
from tkinter import filedialog

def get_file_path():
    # Open and return file path
    file_path= filedialog.askopenfilename(title = "Select A File", filetypes = (("mov files", "*.png"), ("mp4", "*.mp4"), ("wmv", "*.wmv"), ("avi", "*.avi")))
    l1 = Label(window, text = "File path: " + file_path).pack()

window = Tk()
# Creating a button to search the file
b1 = Button(window, text = "Open File", command = get_file_path).pack()
window.mainloop()

有人知道这样做的好方法吗？

Answer 1

使用全局变量：

from tkinter import *
from tkinter import filedialog

def get_file_path():
    global file_path
    # Open and return file path
    file_path= filedialog.askopenfilename(title = "Select A File", filetypes = (("mov files", "*.png"), ("mp4", "*.mp4"), ("wmv", "*.wmv"), ("avi", "*.avi")))
    l1 = Label(window, text = "File path: " + file_path).pack()

window = Tk()
# Creating a button to search the file
b1 = Button(window, text = "Open File", command = get_file_path).pack()
window.mainloop()
print(file_path)

关闭窗口后，您将获得文件路径。