如何调用在Web API中接受相同参数类型的GET方法

问题描述 投票:-1回答:2

我有一个名为Problems的模型,它具有Id和严重性属性,它们是整数和一个问题控制器,它应该处理GET请求并返回所有问题和严重性。由于Dotnet API不支持相同的参数类型,如int,我该怎么做?

我尝试使用不同的方法名称,如Get()GetBySeverity(int severity),但出现了模棱两可的异常。

这是我的控制器

[Route("api/[controller]")]
[ApiController]
public class IssuesController : ControllerBase
{   

    [HttpGet(Name="issues")]
    public IEnumerable<Issue> GetAllIssues() {
            IssueService service = new IssueService();
            return service.GetIssues();
}

    [HttpGet]
    public IEnumerable<Issue> GetBySeverity([FromQuery(Name="severity")]int severity)
    {
        IssueService service = new IssueService();
        return service.GetIssuesBySeverity(severity);

    }


}

这些是我想要发展的api /api/issues//api/issues/?severity=1

c# .net asp.net-web-api
2个回答
0
投票

像这样

//GET api/issues/5
[HttpGet("{id}")]
public Issue GetByRoute([FromRoute(Name="id")] int id)
{
    IssueService service = new IssueService();
    return service.GetIssueById(id);
}   


[HttpGet()]
public Issue GetByQuery([FromQuery(Name="severity")] int severityId)
{
   IssueService service = new IssueService();
   return service.GetIssueById(severityId);
}   

0
投票

有一个模棱两可的参考,因为两个动作都是HttpGet,路由引擎无法决定采取哪条路线或你的意思。

Web Api控制器使用HttpVerbs而不是动作/方法名称(如MVC)进行路由。

我会用Attribute routing with Http[Verb] attributes。这使用Route("myroute")来定义路线。

// GET api/issues/severity/5
[Route("severity/{severity}")]
[HttpGet()]
public IEnumerable<Issue> GetBySeverity(int severity)
{
    IssueService service = new IssueService();
    return service.GetIssuesBySeverity(severity);
}

// GET api/issues/5
[HttpGet("{id}")]
public Issue Get(int id)
{
    IssueService service = new IssueService();
    return service.GetIssueById(id);
}   

上述方法将路由到api/issues/1api/issues/severity/1。如果你想使用查询参数而不是url param进行映射,那么下面应该可以工作:

// GET api/issues/severity?severity=5
[HttpGet("severity")]
public IEnumerable<Issue> GetBySeverity([FromQuery] int severity)
{
    IssueService service = new IssueService();
    return service.GetIssuesBySeverity(severity);
}

// GET api/issues?id=5
[HttpGet()]
public Issue Get([FromQuery] int id)
{
    IssueService service = new IssueService();
    return service.GetIssueById(id);
} 

以上行动将路由到api/issues?id=1api/issues/severity?severity=1

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