将联系人号码与android中的firebase数据库电话号码进行比较时出错

问题描述 投票:-1回答:2
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我的应用程序是crush错误比较联系人号码与user error.add(mUser)中android ERROR中的firebase数据库电话号码;在MainActivity中:[在此输入图像描述] [1]

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E / AndroidRuntime:致命异常:主要

    java.lang.NullPointerException
        at com.example.mohaiminur.com.whatp.MainActivity$LoadContact$1.onDataChange(MainActivity.java:160)
        at com.google.firebase.database.zzp.onDataChange(Unknown Source)
        at com.google.android.gms.internal.firebase_database.zzfc.zza(Unknown Source)
        at com.google.android.gms.internal.firebase_database.zzgx.zzdr(Unknown Source)
        at com.google.android.gms.internal.firebase_database.zzhd.run(Unknown Source)
        at android.os.Handler.handleCallback(Handler.java:800)
        at android.os.Handler.dispatchMessage(Handler.java:100)
        at android.os.Looper.loop(Looper.java:194)
        at 
android firebase firebase-realtime-database contacts android-contacts
2个回答
1
投票

你永远不会在任何地方初始化userList。当你调用给出userlist.add(mUser);NullPointerException时,因为你无法将用户添加到不存在的列表中。

要解决此问题,请在尝试向其添加用户之前创建列表。例如,在onCreate中:

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    recyclerView = (RecyclerView) findViewById(R.id.contacts_list);
    recyclerView.setHasFixedSize(true);

    recyclerView.setLayoutManager(layoutManager);
    selectUsers = new ArrayList<Contacts>();
    showContacts();

    userList = new ArrayList<>();
}

0
投票

您的ArrayList没有初始化这就是您的应用程序崩溃的原因。首先初始化您的ArrayList。

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    recyclerView = (RecyclerView) 
                findViewById(R.id.contacts_list);
    recyclerView.setHasFixedSize(true);

    recyclerView.setLayoutManager(layoutManager);
    selectUsers = new ArrayList<Contacts>();
    userlist = new ArrayList<Contacts>();
    showContacts();

}

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