TaxCalculator函数Javascript代码不起作用

Question

const taxCalculator (price, state) => {
    let state = 'NY' || 'NJ';
     if (state === 'NY'){
        return price * 1.04;
    } else {
        return price * 1.06625;
    }
}

//我被要求定义一个名为taxCalculator的函数，该函数接受商品和州的价格。 taxCalculator应该产生税后金额。如果NY-4％的营业税和NJ是6.625％的营业税。

谢谢！

Answer 1

固定您的代码，请尝试以下操作：

const taxCalculator = (price, state) => {
if (state === 'NY' ) {
    return price * 1.04;
  } else {
    return price * 1.06625;
  }
}

console.log（taxCalculator（100，'NY'））;

Answer 2

箭头功能语法：

缺少第一个=

|var, const, let| identifier = (@param1, ...@paramN) => {...
  ...
  return result;
}

const taxCalculator = (price, state) => {...

[state已经声明为第二个参数-删除let以使其有效-删除整个表达式，因为它没有用：

let state = 'NY' || 'NJ';

if/else语句是否已经分类，如果state为'NY'。上面的表达式甚至没有真正定义，修改等。state完全没有。

---

演示

注意：演示中评论了详细信息

/*
= Two ternaries:
- if state is 'NY' [?] then tax is 1.04
  [:] if state is 'NJ' [?] then tax is 1.06625
  [:] otherwise tax is nothing
- if tax is nothing [?] then return a message
  [:] otherwise return the product of price and tax as a
      String prefixed by '$' and truncated to 2 decicimals.
*/
const taxCalculator = (price, state) => {
  let tax = state === 'NY' ? 1.04 : state === 'NJ' ? 1.06625 : null;
  return tax === null ? `${state} not recognized` : '$' + (price * tax).toFixed(2);
}

console.log(taxCalculator(5.29, 'NJ'));
console.log(taxCalculator(5.29, 'CA'));
console.log(taxCalculator(5.29, 'NY'));

Answer 3

这是错误的，您的“状态”变量是函数的参数。请尝试：

const taxCalculator(price,state)=>{
  return (price * (state==='NY'?1.04:1.06625))
}

此外，如果要支持NY和NJ以外的其他情况，可以在内部使用switch函数来比较“ state”变量值。