“ C中的open()函数中的“权限被拒绝”

问题描述 投票:0回答:2

我是C编程新手。我在使用C语言中的open()函数写入文件时遇到问题,为清楚起见,这是我的代码

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <fcntl.h>
#include <sys/stat.h>
#include <unistd.h>

void usage(char *prog_name, char *filename){
    printf("Usage: %s <data to add to %s> \n",prog_name, filename);
    exit(0);
}

void fatal(char *);                          
void *errchck_malloc(unsigned int);     

int main(int argc, char *argv[]){
    int fd; // File descriptor
    char *buffer, *datafile;

    buffer = (char *) errchck_malloc(100);
    datafile = (char *) errchck_malloc(20);
    strcpy(datafile, "./simplenote.txt");

    if (argc < 2)
        usage(argv[0], datafile);

    strcpy(buffer, argv[1]);

    printf("[DEBUG] buffer @ %p: \'%s\'\n", buffer, buffer);
    printf("[DEBUG] datafile @ %p: \'%s\'\n", datafile, datafile);

    strncat(buffer, "\n", 1);

    // Open file 
    fd = open(datafile, O_CREAT|O_RDWR,O_APPEND, S_IRUSR, S_IWUSR);
    if(fd == -1)
        fatal("in main() while opening file");
    printf("[DEBUG] file descriptor is %d\n", fd);

    // Writing data to file
    if(write(fd, buffer, strlen(buffer))==-1)
        fatal("in main() while writing buffer to file");

    // Closing file
    if(close(fd) == -1)
        fatal("in main() while closing file");

    printf("Note saved\n");
    free(buffer);
    free(datafile);
}

// fatal(): Function to display error message then exit
void fatal(char *message){
    char err_msg[100];

    strcpy(err_msg, "[!!] Fatal Error ");
    strncat(err_msg, message, 83);
    perror(err_msg);
    exit(-1);
}

// errchck_malloc(): An error check malloc wrapper function
void *errchck_malloc(unsigned int size){
    void *ptr;
    ptr = malloc(size);
    if(ptr == NULL)
        fatal("in errchck_malloc() on memory allocation");
    return ptr;
}

当我第一次尝试执行程序时,程序将按预期运行。

首次运行:

user: ./simplenote "Hello, again"
[DEBUG] buffer @ 0x7fafcb4017a0: 'Hello again'
[DEBUG] datafile @ 0x7fafcb401810: './simplenote.txt'
[DEBUG] file descriptor is 3
Note saved

当我尝试打开文件并查看文本时,出现权限被拒绝的错误。当我尝试使用sudo打开文件时,它将打开并且文本在文件中。当我第二次运行程序时,由于权限问题,打开文件时出现错误。

第二次运行:

user: ./simplenote "just checking if it is still working"                                                           
[DEBUG] buffer @ 0x7face4c017a0: 'just checking if it is still working'
[DEBUG] datafile @ 0x7face4c01810: './simplenote.txt'
[!!] Fatal Error in main() while opening file: Permission denied

如何解决文件创建中的权限问题?

c file-access
2个回答
2
投票
首次运行程序时创建的文件具有不允许您追加的权限

0
投票
open()的参数不正确。 documentation of open()说:
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