如何通过单击Next按钮和Previous按钮浏览文件夹中的文件，然后在表格单元格中显示文件内容？
这是我的示例输出，但遗憾的是它不适合我：
这是我使用的代码：
<!DOCTYPE html>
<html>
<head>
<title>Browse Files</title>
</head>
<body>
<?php
$dir = '/xampp/htdocs/files';
$file = array_diff(scandir($dir), array('.','..'));
function showContent($fdata) {
$fopen = fopen($fdata,'r') or die ("Could not open file");
$content = fread($fopen,filesize($fdata)) or die("Could not read the file");
echo $content;
fclose($fopen);
}
?>
<table border = "1" cellpadding = "10" align = "center" width = "500">
<frame method = "post" action = "<?php echo $_SERVER['PHP_SELF']; ?>">
<tr>
<td>
<h3>File Contents: </h3> <br />
<?php
if (isset($_POST['next'])) {
for($i = 0; $i < sizeof($file); $i++) {
$path = $dir ."/". $file[$i];
showContent($path);
}
}
if (isset($_POST['previous'])) {
for($x = sizeof($file); $x > sizeof($file); $i--) {
$path = $dir ."/". $file[$i];
showContent($path);
}
}
?>
</td>
</tr>
<td align = "center">
<input type = "submit" name = "previous" value = "Previous">
<input type = "submit" name = "next" value = "Next">
</td>
</frame>
</table>
</body>
</html>
除了首先获取文件夹的内容之外，我无法想到任何方法：
# You want to feed in the base directory, the current file path, and whether
# to advance or previous
function getContents($dir,$current = false,$advance = false)
{
# You don't want to get the file contents of images, it's garbled
$img = ['gif','jpg','jpeg','png'];
# Get the contents of the folder and remove directories and dots
$contents = array_values(array_filter(scandir($dir),function($v) use ($dir){
if(in_array($v,['.','..']))
return false;
if(is_dir($dir.'/'.$v))
return false;
return true;
}));
# If no current file, grab the first one
if(empty($current)) {
if(!empty($contents)) {
$nPath = array_shift($contents);
$next = $dir.'/'.$nPath;
return [
'img' => (is_file($next) && in_array(strtolower(pathinfo($next,PATHINFO_EXTENSION)),$img)),
'file' => (is_file($next))? basename($next) : false,
'current'=> (!empty($nPath))? $next : false,
'data'=>(!empty($nPath) && is_file($next))? file_get_contents($next) : false
];
}
}
else {
# If there is a current file being viewed..
foreach($contents as $key => $value) {
# See if this file is the file being viewed
if($dir.'/'.$value == $current) {
# If want to see next, get the next key
if($advance == 'next')
$nPath = (!empty($contents[$key+1]))? $contents[$key+1] : $contents[0];
# Rewind the current array
else {
prev($contents);
prev($contents);
$nPath = (!empty($contents[key($contents)]))? $contents[key($contents)] : $contents[$key];
}
$next = $dir.'/'.$nPath;
return [
'img' => (is_file($next) && in_array(strtolower(pathinfo($next,PATHINFO_EXTENSION)),$img)),
'file' => (is_file($next))? basename($next) : false,
'current'=>$next,
'data'=>(!empty($nPath) && is_file($next))? file_get_contents($next) : false
];
}
}
}
}
# Set the action
$action = (!empty($_POST['action']))? strtolower($_POST['action']) : false;
# Capture current path
$curr = (!empty($_POST['current']))? $_POST['current'] : false;
# Retrieve the next or prev
$contents = getContents(__DIR__,$curr,$action);
?>
<table border = "1" cellpadding = "10" align = "center" width = "500">
<tr>
<td>
<h3>File Contents: <?php echo $contents['file'] ?></h3> <br />
<?php if(!empty($contents['img'])): ?>
<img src="<?php echo str_replace($_SERVER['DOCUMENT_ROOT'],'',$contents['current']) ?>" style="max-width: 100px;" />
<?php else: ?>
<pre><?php echo htmlspecialchars($contents['data']) ?></pre>
<?php endif ?>
</td>
</tr>
<td align = "center">
<form method="POST" action="">
<input type="hidden" name="current" value="<?php echo $contents['current'] ?>" />
<input type = "submit" name="action" value = "Previous">
<input type = "submit" name="action" value = "Next">
</form>
</td>
</frame>
</table>
</body>
</html>
你可能需要对此进行一些细化，但它非常接近......我不知道它有多高效。