我叫Syarz,我是编程新手。我想知道如何使用cmd或批处理文件从字符串中删除字符。
这是data.txt文件中的字符串:
test.rar:$rar5$16$b19108e5cf6a5dadaa0ff515f59c6df7$15$f7f4933a2a8f7aa43d7fc31e86c47e2b$8$307ef2987e735bec
我在运行命令或data.txt中的批处理文件后需要这个
$rar5$16$b19108e5cf6a5dadaa0ff515f59c6df7$15$f7f4933a2a8f7aa43d7fc31e86c47e2b$8$307ef2987e735bec
我已经尝试了网站上提供的几种方法,但是似乎没有一种对我有用。他们要么删除整个字符串,要么删除我不想要的部分。
我已经尝试过的内容
1-
more +1 "data.txt" > "data_NEW.txt"
2-
@echo off
(
for /F usebackq^ skip^=1^ delims^=^ eol^= %%L in ("data.txt") do echo(%%L
) > "data_NEW.txt"
3-
@echo off
(
for /F "skip=1 delims=" %%L in ('findstr /N "^" "data.txt"') do (
set "LINE=%%L"
setlocal EnableDelayedExpansion
echo(!LINE:*:=!
endlocal
)
) > "data_NEW.txt"
4-
@echo off
for /F %%C in ('find /C /V "" ^< "data.txt"') do set "COUNT=%%C"
setlocal EnableDelayedExpansion
(
for /L %%I in (1,1,%COUNT%) do (
set "LINE=" & set /P LINE=""
if %%I gtr 1 echo(!LINE!
)
) < "data.txt" > "data_NEW.txt"
endlocal
5-
void chopN(char *str, size_t n)
{
assert(n != 0 && str != 0);
size_t len = strlen(str);
if (n > len)
return; // Or: n = len;
memmove(str, str+n, len - n + 1);
}
6-
void chopN(char *str, size_t n) {
char *dest = str;
// find beginning watching out for rump `str`
while (*str && n--) {
str++;
}
// Copy byte by byte
while (*src) {
*dest++ = *src++;
}
*dest = '\0';
}
7-
for /f %%a in (input.txt) do set "line=%%a"
set "line=%line:pub:04:=%"
set "line=%line::=%"
echo %line%
8-
@echo off
setlocal enabledelayedexpansion
set "first=true"
(for /f "eol=p delims=" %%a in (input.txt) do (
set "line=%%a"
if defined first (set "line=!line:~2!" & set "first=")
<nul set /p ".=!line::=!"
))>output.txt
只是尝试学习新知识。谢谢大家。
[我知道您要批处理,但我没有提供批处理答案,所以我会帮助您的人员返回批处理答案。
这是执行PowerShell的简单方法:
$f = Get-Content data.txt
$out = 'data2.txt'
$f | ForEach-Object {
$_.Split(':')[1]
} | Out-File $out -Append