具有不同计数的案例列表

Question

我希望需要以下查询才能工作：

select tbl.depno
,  case
                 when count(distinct ntl.number) over(partition by tbl.id) > 1 
                 then listagg(ntl.number, ',') within group (order by ntl.number) 
              
                 else 'test'
                end as multiple_number

from table tbl,
notable ntl
where tbl.id = ntl.id
group by tbl.depno

这样就可以了：

select tbl.depno
, listagg(ntl.number, ',') within group (order by ntl.number)

from table tbl,
notable ntl
where tbl.id = ntl.id
group by tbl.depno

但是我需要它在我的情况下工作，当实际上有更多数字时，然后聚合，如果只有一个，那么它必须插入文本（现在，测试）

所以当我运行第一部分时收到的错误消息是：

ORA--00979: not a GROUP BY expression

Answer 1

SELECT 
    tbl.depno,
    CASE
        WHEN count(distinct ntl.number) over(partition by tbl.id) > 1 
        THEN listagg(ntl.number, ',') WITHIN GROUP (ORDER BY ntl.number) 
        ELSE 'test'
    END AS multiple_number
FROM 
    table tbl
JOIN 
    notable ntl ON tbl.id = ntl.id
GROUP BY 
    tbl.depno, tbl.id;