如何从类中的方法动态创建模块级函数

问题描述 投票:0回答:3

我正在尝试从类中的方法动态创建模块级函数。因此,对于类中的每个方法,我想创建一个具有相同名称的函数,该函数创建该类的实例,然后调用该方法。

我想这样做的原因是我可以采用面向对象的方法来创建 Fabric 文件。由于 Fabric 将调用模块级函数而不是类的方法,这是我的解决方法。

我已使用以下链接开始使用

我想出了以下代码

import inspect
import sys
import types

class TestClass(object):
    def __init__(self):
        pass

    def method1(self, arg1):
        print 'method 1 %s' % arg1

    def method2(self):
        print 'method 2'

def fabric_class_to_function_magic(module_name):
    # get the module as an object
    print module_name
    module_obj = sys.modules[module_name]
    print dir(module_obj)

    # Iterate over the methods of the class and dynamically create a function
    # for each method that calls the method and add it to the current module
    for method in inspect.getmembers(TestClass, predicate=inspect.ismethod):
        print
        print method
        method_name, method_obj = method

        # create a new template function which calls the method
        def newfunc_template(*args, **kwargs):
            tc = TestClass()
            func = getattr(tc, method_name)
            return func(*args, **kwargs)

        # create the actual function
        print 'code: ', newfunc_template.func_code
        print 'method_name: ', method_name
        newfunc = types.FunctionType(newfunc_template.func_code,
                                     {'TestClass': TestClass,
                                      'getattr': getattr,
                                      'method_name': method_name,
                                      },
                                     name=method_name,
                                     argdefs=newfunc_template.func_defaults,
                                     closure=newfunc_template.func_closure,
                                     )

        # add the new function to the current module
        setattr(module_obj, method_name, newfunc)

# test the dynamically created module level function
thismodule = sys.modules[__name__]
print dir(thismodule)
fabric_class_to_function_magic(__name__)
print dir(thismodule)
method1('arg1')
method2()

我收到以下错误

['TestClass', '__builtins__', '__doc__', '__file__', '__name__', '__package__', 'fabric_class_to_function_magic', 'inspect', 'sys', 'thismodule', 'types']
__main__
['TestClass', '__builtins__', '__doc__', '__file__', '__name__', '__package__', 'fabric_class_to_function_magic', 'inspect', 'sys', 'thismodule', 'types']

('__init__', <unbound method TestClass.__init__>)
code:  <code object newfunc_template at 0x7f8800a28d50, file "test.py", line 85>
method_name:  __init__

('method1', <unbound method TestClass.method1>)
code:  <code object newfunc_template at 0x7f8800a28d50, file "test.py", line 85>
method_name:  method1

('method2', <unbound method TestClass.method2>)
code:  <code object newfunc_template at 0x7f8800a28d50, file "test.py", line 85>
method_name:  method2
['TestClass', '__builtins__', '__doc__', '__file__', '__init__', '__name__', '__package__', 'fabric_class_to_function_magic', 'inspect', 'method1', 'method2', 'sys', 'thismodule', 'types']
Traceback (most recent call last):
  File "test.py", line 111, in <module>
    method1('arg1')
  File "test.py", line 88, in newfunc_template
    return func(*args, **kwargs)
TypeError: method2() takes exactly 1 argument (2 given)

好像是重用了函数的引用?有什么想法吗?

更新:这是经过 Ned Batchelder 修复后的工作代码

def fabric_class_to_function_magic(module_name):
    # get the module as an object
    module_obj = sys.modules[module_name]

    # Iterate over the methods of the class and dynamically create a function
    # for each method that calls the method and add it to the current module
    for method in inspect.getmembers(TestClass, predicate=inspect.ismethod):
        method_name, method_obj = method

        # get the bound method
        tc = TestClass()
        func = getattr(tc, method_name)

        # add the function to the current module
        setattr(module_obj, method_name, func)

更新2:这是我关于该主题的博客文章:http://www.saltycrane.com/blog/2010/09/class-based-fabric-scripts-metaprogramming-hack/

python metaprogramming fabric
3个回答
9
投票

你的解决方案想得太多了。将

fabric_class_to_function_magic
的结尾更改为:

    tc = TestClass()
    func = getattr(tc, method_name)

    # add the new function to the current module
    setattr(module_obj, method_name, func)

而且效果很好。无需创建新的函数对象,您的对象上已经有 getattr 返回的函数对象。 getattr 返回的绑定方法是一个可调用的东西。只需将其分配给您的模块属性,就可以开始了。


1
投票

实际上你的代码是正确的,但是当 return func(*args, **kwargs) 执行时,args 将传递像 () 这样的空元组,并且你的 method2 中没有参数,所以它引发了这样的异常,

解决您问题的快速解决方案是,例如

class TestClass(object):
    def __init__(self):
        pass

    def method1(self, arg1):
        print 'method 1 %s' % arg1

    def method2(self, *args, **kw):
        print 'method 2'

0
投票

这可能对某人有用:

import inspect
import sys

def get_functions_from_class_in_module_and_extract_to_module(module, *args, class_config={}, **kwargs):

    classes = dict(tuple(x) for x in inspect.getmembers(sys.modules[module.__name__], inspect.isclass))

    for cls_name, cls in classes.items():

        class_instance = cls(**class_config[cls_name])

        functions = dict(tuple(x) for x in inspect.getmembers(cls, inspect.isfunction))

        for function_name, func in functions.items():
                
            class_func = lambda *args, **kwargs: func(class_instance, *args, **kwargs)

            setattr(module, function_name, class_func)
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