我将如何操作重载“ <

Question

我的教授说，<

这是我的代码中的一个函数：

void listProducts()
{
    //list all the available products.
    cout << "Available products:\n";
    for(int i=0; i<numProducts; i++)
        cout << products[i]->getCode() << ": " << products[i]->getName() << " @ "
             << products[i]->getPrice() << "/pound.\n";
}

这是product.cpp文件：

Product :: Product(int code, string name, double price) {
this->code = code;
this->name = name;
this->price = price;
}

int Product:: getCode(){
return code;
}

string Product :: getName(){
return name;
}

double Product :: getPrice(){
return price;
}

Answer 1

您可以做类似的事情

std::ostream & operator<<(std::ostream &out,const classname &outval)
{
    //output operation like out<<outval.code<<":"<<outval.name<<"@"<<outval.price;
    return out;
}

和

friend std::ostream & operator<<(std::ostream &out,const classname &outval);

在您的班上访问私人成员。

Answer 2

如果您了解上一个问题this的解决方案，那么了解以下代码非常容易。唯一的区别是使用了朋友功能，您可以通过该功能来阅读gfg link。

为了更好地理解，下面给出了完全相同的示例，

#include <iostream>
using namespace std;

class Product
{
private:
    int code; string name; double price;
public:
    Product(int, string, double);
    friend ostream & operator << (ostream &out, const Product &p);

};

Product :: Product(int code, string name, double price) {
    this->code = code;
    this->name = name;
    this->price = price;
}

ostream & operator << (ostream &out, const Product &p)
{
    out<< p.code << ": " << p.name << " @ "
             << p.price << "/pound.\n";
    return out;
}


int main()
{
   Product book1(1256,"Into to programming", 256.50);
   Product book2(1257,"Into to c++", 230.50);
   cout<<book1<<endl<<book2;
   return 0;
}