RapidAPI：如何在 booking.com 中找到 hotel_id？

Question

我正在使用来自 RapidAPI 的 Booking.com API。我想获得酒店的评论，但我不知道如何找到特定酒店的 hotel_id（必填参数）？

import requests

url = "https://booking-com.p.rapidapi.com/v1/hotels/reviews"

querystring = {"hotel_id":"1676161","locale":"en-gb","sort_type":"SORT_MOST_RELEVANT","customer_type":"solo_traveller,review_category_group_of_friends","language_filter":"en-gb,de,fr"}

headers = {
    'x-rapidapi-host': "booking-com.p.rapidapi.com",
    'x-rapidapi-key': "1bed4aac31mshcd4d969233d7d7dp129f0bjsn58eea903e6c2"
    }

response = requests.request("GET", url, headers=headers, params=querystring)

print(response.text)

Answer 1

您可以使用下面的RapidAPI找到hotel_id。

通过过滤器获取可用酒店。指明destination_id 和dest_type -> 使用@Search 位置端点、入住和退房日期、成人和儿童人数。对于可能的过滤器，请使用@Filters进行搜索

import requests

url = "https://booking-com.p.rapidapi.com/v1/hotels/search"

querystring = {"room_number":"1","order_by":"popularity","filter_by_currency":"AED","checkout_date":"2022-07-02","checkin_date":"2022-07-01","units":"metric","adults_number":"2","dest_id":"-553173","dest_type":"city","locale":"en-gb","children_number":"2","children_ages":"5,0","page_number":"0","include_adjacency":"true","categories_filter_ids":"class::2,class::4,free_cancellation::1"}

headers = {
    'x-rapidapi-host': "booking-com.p.rapidapi.com",
    'x-rapidapi-key': "0195db92d0msh8afac0130adb2c4p1087e9jsn2aeab9e0aa0f"
    }

response = requests.request("GET", url, headers=headers, params=querystring)

print(response.text)

结果如下。

"result": [
    {
      "id": "property_card_791664",
      "hotel_name": "Cheval Thorney Court at Hyde Park",
      "class_is_estimated": 0,
      "hotel_has_vb_boost": 0,
      "district": "Kensington and Chelsea",
      "cant_book": null,
      "distance_to_cc": "4.00",
      "mobile_discount_percentage": 0,
      "is_mobile_deal": 0,
      "is_free_cancellable": 0,
      "countrycode": "gb",
      "latitude": 51.5011118011927,
      "districts": "1545,29,44,333,2280",
      "city_name_en": "London",
      "min_total_price": 379.24,
      "hotel_id": 791664,
      ...

可以从结果中获取hotel_id。

访问 https://rapidapi.com/tipsters/api/booking-com/tutorials/booking-api-tutorial-1

谢谢。

Answer 2

我给你两种方法：一种是手动，另一种是使用Python代码。理解第一种方法将帮助您了解第二种方法的工作原理。

手册

1. 打开 booking.com 上您想要查找的酒店页面 hotel_id。
2. 右键单击页面并选择 Inspect 打开 Chrome 开发者工具。
3. 导航到开发人员工具中的“控制台”选项卡。
4. 输入以下 JavaScript 命令并按 Enter：

document.querySelector('input[name="hotel_id"]').value

此命令查找

input

属性设置为

name

的

hotel_id

元素，并检索其

value

，它对应于酒店的 ID。

Python

先决条件：

确保您的 Python 环境中安装了

requests

和

beautifulsoup4

。如果没有，您可以使用 pip 安装它们：

pip install requests beautifulsoup4

Python代码：

import requests
from bs4 import BeautifulSoup

# Replace 'YOUR_HOTEL_PAGE_URL' with the actual URL of the hotel page on booking.com
url = 'YOUR_HOTEL_PAGE_URL'

# Fetch the content of the hotel page
response = requests.get(url)

# Parse the HTML content of the page
soup = BeautifulSoup(response.text, 'html.parser')

# Find the input element with name='hotel_id' and get its value
hotel_id = soup.find('input', {'name': 'hotel_id'})['value']

print(f'The hotel_id is: {hotel_id}')