HTTP POST请求发送的JSONObject与排球

问题描述 投票:1回答:2

我试图让通过在Android凌空库中的HTTP POST请求。

其实,我想检索API返回给我的JSON对象。

API文档给我,这个工作要求卷曲:

curl -H "Authorization: Token $API_KEY" \
    --header "Content-Type: application/json" \
    --compressed \
    --data @- \
    https://api.idbus.com/v1/search <<JSON
      {
        "origin_id": 1,
        "destination_id": 17,
        "date": "2015-08-15",
        "passengers": [
          { "id": 1, "age": 30 },
          { "id": 2, "age": 30 },
          { "id": 3, "age": 1 }
        ]
      }
JSON

但我想将其转换为与排球的HTTP请求。

问题是,当我启动我的代码,我得到一个404错误,而卷曲请求工作。

我认为这个问题是来自我通过JSON对象到请求的方式。但我没有找到错误,我希望有人能帮帮我,谢谢你在前进!

这里是我的代码:

    String url = "https://api.idbus.com/v1/search";
    final JSONObject jsonBody = new JSONObject();
    JSONArray passengers = new JSONArray();

    try {
        passengers.put(getPerson(1, 30));
        passengers.put(getPerson(2, 30));
        passengers.put(getPerson(3, 1));
    } catch (JSONException e){
        e.printStackTrace();
    }
    try {
        jsonBody.put("origin_id", 1);
        jsonBody.put("destination_id", 17);
        jsonBody.put("date", "2015-08-15");
        jsonBody.put("passengers", passengers);
    } catch (JSONException e){
        e.printStackTrace();
    }

    JsonObjectRequest stringRequest = new JsonObjectRequest(Request.Method.POST, url, jsonBody,
            new Response.Listener<JSONObject>() {
                @Override
                public void onResponse(JSONObject response) {
                    mTextView.setText(response.toString());
                }
            }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            mTextView.setText("That didn't work!");
        }
    }){
        @Override
        public Map<String, String> getHeaders() throws AuthFailureError {
            Map<String,String> params = new HashMap<String, String>();
            params.put("Authorization", "Token EnVo01jqN2XJIAd8vlLkw");
            params.put("Content-Type","application/json");
            return params;
        }
    };
    queue.add(stringRequest);
}
JSONObject  getPerson(int id, int age) throws JSONException {
    JSONObject person = new JSONObject();
    person.put("id", id);
    person.put("age", age);
    return person;
}

我的JSON对象是这样的:

    {  
       "origin_id":1,
       "destination_id":17,
       "date":"2015-08-15",
       "passengers":[  
          {  
             "id":1,
             "age":30
          },
          {  
             "id":2,
             "age":30
          },
          {  
             "id":3,
             "age":1
          }
       ]
    }
java android http http-post android-volley
2个回答
1
投票

尝试从final失去jsonBody的JSONObject

编辑:

您发送int类型为字符串,所以对对方服务器也许就不会那么乐意了:你送什么:

 {"origin_id":"1",
"destination_id":"17",
"date":"2015-08-15",
"passengers":[{"id":"1","age":"30"},{"id":"2","age":"30"},{"id":"3","age":"1"}]}

你应该送:

{"origin_id":1,
"destination_id":17,
"date":"2015-08-15",
"passengers":[{"id":1,"age":30},{"id":2,"age":30},{"id":3,"age":1}]}

采用:

try {
            passengers.put(getPerson(1, 30));
            passengers.put(getPerson(2, 30));
            passengers.put(getPerson(3, 1));
        } catch (JSONException e){
            e.printStackTrace();
        }
        try {
            jsonBody.put("origin_id", 1);
            jsonBody.put("destination_id", 17);
            jsonBody.put("date", "2015-08-15");
            jsonBody.put("passengers", passengers);
        } catch (JSONException e){
            e.printStackTrace();
        }

getPerson现在看起来应该使用的,而不是为intString id age

JSONObject getPerson(int id, int age) throws JSONException

编辑2 - 什么工作

嗯,请尝试使用邮差(getpostman.com),并提交从那里同岗看到,抛出什么样的错误你,事情可能是一个服务器端的问题


0
投票
params.put("Authorization", "Token EnVo01jqN2XJIAd8vlLkw");

删除Token文本:

params.put("Authorization", "EnVo01jqN2XJIAd8vlLkw");
© www.soinside.com 2019 - 2024. All rights reserved.