以下是我尝试将https://
添加到URL的两种方法。由于某种原因,urljoin方法给出了奇怪的输出:
from requests.compat import urljoin
host = 'abc.def.com'
host2 = host
# brute-force string method
if not host.startswith('https://'):
host = 'https://' + host # Add schema
if host.endswith('/'):
host = host[:-1] # Strip /
print('Stringy way', host)
# nice library method? Doesn't quite work
print('urljoin ', urljoin('https://', host2))
我看到的输出,奇怪的三个///字符,是
Stringy way https://abc.def.com
urljoin https:///abc.def.com
我也得到了其他变种的无效结果:
print('urljoin #2 ', urljoin('https:/', host2))
print('urljoin #3 ', urljoin('https:', host2))
print('urljoin #4 ', urljoin('https', host2))
得到:
urljoin #2 https:///abc.def.com
urljoin #3 https:///abc.def.com
urljoin #4 abc.def.com
这是错误的功能吗?
您可以使用urllib.parse.urlunsplit()
撰写网址:
from urllib.parse import urlunsplit
print(urlunsplit(("https", "abc.def.com", "", "", "")))
结果:
https://abc.def.com
它需要一个元组作为输入,匹配urlsplit()
的输出,以及元组的以下属性:
urljoin函数通常用于将href锚附加到现有url。例:
from requests.compat import urljoin
url = 'https://abc.def.com'
href = '364'
urljoin(url, href)
我得到输出: -
'https://abc.def.com/364'
但是,如果我想用'https://'填写我的网址,我宁愿使用: -
from requests.compat import urljoin
url = 'abc.def.com'
host = ('https://'+ url)
print(host)
我的输出是:
https://abc.def.com
我希望这有帮助。