如何在不使用 distutils 的情况下对版本列表进行排序?
distutils.version
版本号的长度有限制,所以我得到
msg": "invalid version number '11.2.0.4.v4'"
"results": null
["11.2.0.4.v4", "11.2.0.4.v5", "11.2.0.4.v6", "11.2.0.4.v7", "11.2.0.4.v8",
"11.2.0.4.v9", "11.2.0.4.v10", "11.2.0.4.v11", "11.2.0.4.v12",
"11.2.0.4.v13", "11.2.0.4.v14", "11.2.0.4.v15", "11.2.0.4.v16",
"11.2.0.4.v17", "12.1.0.2.v1", "12.1.0.2.v2", "12.1.0.2.v3", "12.1.0.2.v4",
"12.1.0.2.v5", "12.1.0.2.v6", "12.1.0.2.v7", "12.1.0.2.v8", "12.1.0.2.v9",
"12.1.0.2.v10", "12.1.0.2.v11", "12.1.0.2.v12", "12.1.0.2.v13"]
try:
params = dict()
params['Engine'] = module.params.get('engine_name')
results = client.describe_db_engine_versions(**params)
versions = [z['EngineVersion'] for z in results['DBEngineVersions']]
return versions.sort(key=StrictVersion)
except Exception as e:
module.fail_json(msg=str(e))
packaging.version.Version
来完成,但在这种情况下不起作用,因为根据 规范,字符串不是有效的版本号。
>>> from packaging.version import parse
>>> parse("11.2.0.4.v4")
InvalidVersion: Invalid version: '11.2.0.4.v4'
您可以使用 looseversion 来订购这些字符串。它是已弃用的
distutils.version.LooseVersion
类型的向后/向前兼容的分支,适用于不希望对数据进行严格的 PEP 440 约束的情况。
>>> from looseversion import LooseVersion
>>> sorted(vs, key=LooseVersion)
['11.2.0.4.v4',
'11.2.0.4.v5',
'11.2.0.4.v6',
'11.2.0.4.v7',
'11.2.0.4.v8',
'11.2.0.4.v9',
'11.2.0.4.v10',
'11.2.0.4.v11',
'11.2.0.4.v12',
'11.2.0.4.v13',
'11.2.0.4.v14',
'11.2.0.4.v15',
'11.2.0.4.v16',
'11.2.0.4.v17',
'12.1.0.2.v1',
'12.1.0.2.v2',
'12.1.0.2.v3',
'12.1.0.2.v4',
'12.1.0.2.v5',
'12.1.0.2.v6',
'12.1.0.2.v7',
'12.1.0.2.v8',
'12.1.0.2.v9',
'12.1.0.2.v10',
'12.1.0.2.v11',
'12.1.0.2.v12',
'12.1.0.2.v13']