由于列中有两个以上的双引号，sqlldr失败

Question

问题是当我在NAME列中放入两个以上的双引号（检查下面的代码）然后sqlldr失败。在data.txt文件中，前3条记录失败，因为NAME列（记录中的第2个位置）有两个以上的双引号。请协助。我认为我需要将一些函数放在NAME列的控制文件中。

您可以运行以下代码并检查，前3条记录将失败，最后一条记录将被插入，我想插入所有带或不带双引号的记录：

--table creation
    create table employee
    (      
      name varchar2(4000)      
    );


--control file
load data
 infile '/tmp/swetabh/data.txt' 
 into table employee
 truncate
 fields terminated by "," OPTIONALLY ENCLOSED by '"'  TRAILING NULLCOLS 
 (
 name      
 )


--data.txt (SEE ALL RECORDS ARE HAVING MORE THAN 2 DOUBLE QUOTE AND WANT TO INSERT DATA TO THE TABLE WITH OR WITHOUT DOUBLE QUOTE)
""start with double quote       "
"end with double quote          ""
"double quote " in the middle   "

-bash-4.1 $ sqlldr userid = xxx / xxx @ xxxx control = / tmp / swetabh / control.txt log = / tmp / swetabh / control.log bad = / tmp / swetabh / bad.txt readsize = 2000000000 bindsize = 2000000000

Answer 1

您是否可以控制流程的提取部分？如果是这样，你可以指定数据中的双引号加倍（引用）吗？或者甚至更好，指定使用管道作为分隔符，没有周围的双引号。

Answer 2

如何应用REPLACE函数将取代双引号（CHR(34)）什么都没有（NULL）？另外，删除OPTIONALLY ENCLOSED条款。

控制文件：

load data 
infile *
replace
into table employee
fields terminated by "," TRAILING NULLCOLS 
(
name "replace(:name, chr(34), null)"    
)

begindata
""start with double quote       "
"end with double quote          ""
"double quote " in the middle   "

测试：

SQL> $sqlldr scott/tiger control=test04.ctl log=test04.log

SQL*Loader: Release 11.2.0.2.0 - Production on Uto O×u 19 19:14:49 2019

Copyright (c) 1982, 2009, Oracle and/or its affiliates.  All rights reserved.

Commit point reached - logical record count 2
Commit point reached - logical record count 3

SQL> select * From employee;

NAME
--------------------------------------------------
start with double quote
end with double quote
double quote  in the middle

SQL>