从对象的数组过滤唯一值[复制]

Question

这个问题已经在这里有一个答案：

• Get all unique values in a JavaScript array (remove duplicates) 74个回答

如何使用Array.filter（）与id返回唯一name？

我的情况是比我已经研究了解决方案，我有对象的数组略有不同。我发现每例子包含单值的平面阵列。

data=[
{id: 555, name: "Sales", person: "Jordan" },
{id: 555, name: "Sales", person: "Bob" },
{id: 555, name: "Sales", person: "John" },
{id: 777, name: "Accounts Payable", person: "Rhoda" },
{id: 777, name: "Accounts Payable", person: "Harry" },
{id: 888, name: "IT", person: "Joe" },
{id: 888, name: "IT", person: "Jake" },
];

var unique = data.filter(
function (x, i) {
   return data[i].id.indexOf(x.id) === i
});

提前致谢。

Answer 1

我认为forEach()是更好地实现你在找什么：

var data=[
{id: 555, name: "Sales", person: "Jordan" },
{id: 555, name: "Sales", person: "Bob" },
{id: 555, name: "Sales", person: "John" },
{id: 777, name: "Accounts Payable", person: "Rhoda" },
{id: 777, name: "Accounts Payable", person: "Harry" },
{id: 888, name: "IT", person: "Joe" },
{id: 888, name: "IT", person: "Jake" },
];
var resArr = [];
data.forEach(function(item){
  var i = resArr.findIndex(x => x.name == item.name);
  if(i <= -1){
    resArr.push({id: item.id, name: item.name});
  }
});
console.log(resArr);

如果你真的想用filter()请尝试以下方法：

var data=[
{id: 555, name: "Sales", person: "Jordan" },
{id: 555, name: "Sales", person: "Bob" },
{id: 555, name: "Sales", person: "John" },
{id: 777, name: "Accounts Payable", person: "Rhoda" },
{id: 777, name: "Accounts Payable", person: "Harry" },
{id: 888, name: "IT", person: "Joe" },
{id: 888, name: "IT", person: "Jake" },
];
var resArr = [];
data.filter(function(item){
  var i = resArr.findIndex(x => x.name == item.name);
  if(i <= -1){
    resArr.push({id: item.id, name: item.name});
  }
  return null;
});
console.log(resArr);