使用 RS 485 MODBUS 和 ARDuino mega 从 Elite 100 电能表读取数据

Question

我正在尝试使用 Arduino Mega 从能量计（型号：ELITE 100，品牌：SECURE）读取 4 个寄存器。我使用 RS 485 转 TTL 模块让 arduino 与电能表进行通信。上传代码后，在串行监视器中我看到arduino无法与电能表通信，并显示十六进制格式的响应代码是“E2”。我无法理解真正的问题是什么。请帮助我。

电能表MODBUS注册链接：https://drive.google.com/drive/folders/1kTQg0wvcX-iG7jkeZHwIUkK8e-9VVVW_?usp=sharing

一些设置值是： 奇偶校验位：无，波特率：9600，停止位：1

代码输出为：

Failed, Response Code: E2

 #include<ModbusMaster.h>
    
    /*  DI =  UNO / NANO TX PIN / arduino mega pin 1 TX pin
                RO =  UNO/ NANO RX PIN / arduino mega pin 0 RX Pin
    */
    #define MAX485_DE      3
    #define MAX485_RE_NEG  2
    
    ModbusMaster node;
    
    void preTransmission() {
      digitalWrite(MAX485_RE_NEG, 1);
      digitalWrite(MAX485_DE, 1);
    }
    
    void postTransmission()
    {
      digitalWrite(MAX485_RE_NEG, 0);
      digitalWrite(MAX485_DE, 0);
    }
    
    void setup() {
      pinMode(MAX485_RE_NEG, OUTPUT);
      pinMode(MAX485_DE, OUTPUT);
      // Init in receive mode
      digitalWrite(MAX485_RE_NEG, 0);
      digitalWrite(MAX485_DE, 0);
    
    
    
      Serial.begin(9600, SERIAL_8N1);
      //slave ID 1
      node.begin(1, Serial);
    
      Serial.println("Starting Modbus Transaction:");
      node.preTransmission(preTransmission);
      node.postTransmission(postTransmission);
    }
    
    uint16_t newData = 0;
    float floatData;
    double dataOne;
    
    void loop() {                           // loop starts from here.
      static uint32_t i;
      uint8_t j, result;
      uint16_t data[10];
    
      i++;
      result = node.readHoldingRegisters(40172, 2); // read holding registars
    
      Serial.println(" ");
      /*
        if (result == node.ku8MBSuccess) {
    
          Serial.print("\nSuccess, Received data 0: ");
    
          for (j = 0; j < 2; j++) {    // THIS FUNCTION READ SINGLE REGISTAR
            data[j] = node.getResponseBuffer(j);
            floatData, dataOne = node.getResponseBuffer(j);
            Serial.print("\nHex data:");
            Serial.print(data[j], HEX);
            Serial.print(" ");
            Serial.print("\nDec data:");
            Serial.print(data[j], DEC);
            Serial.print("\nfloat data:");
            Serial.print(floatData);
      */
    
      if (result == node.ku8MBSuccess) {
    
        Serial.print("\nSuccess, Received data 0: ");
    
        for (j = 0; j < 2; j++) {
          data[j] = node.getResponseBuffer(j);
        }
    
        unsigned long temp = (unsigned long)data[0] + (unsigned long)data[1] * 65536;
        floatData = *((float*)&temp);
    
        Serial.print(floatData);
    
      }
    
      //}
      //}
    
      else {
        Serial.print("Failed, Response Code: ");
        Serial.print(result, HEX);
        Serial.println(" ");
        delay(5000); // 5000
      }
      delay(1000);
    
    }

Answer 1

如果您想获取链接中提到的保持寄存器的值：https://drive.google.com/drive/folders/1kTQg0wvcX-iG7jkeZHwIUkK8e-9VVVW_?usp=sharing

读取V1：R相到中性线电压在初始地址中减1意味着 40100 - 1 = 40099 并仅将 99 传递给代码 Ex。节点.readHoldingRegisters(99, 2)

希望它有效，也感谢Brits