我需要帮助编写Python代码。
我有一个Raspberry Pi3。我有两个执行不同功能的脚本,但我希望它们能够一起工作。
第一个驱动pir传感器,LED作为输出。当pir变高时,它开始倒计时,给予足够的时间再次检测到一个人。在这段时间内如果没有检测到任何东西,LED会熄灭。
第二个驱动LDR传感器。它读取LDR传感器的变化值并打开或关闭LED。我已经为这些设置了所有接线。
主要问题是如何将这两个脚本放在一起,以使pir传感器等到天黑时(来自LDR的值)在检测到/未检测到人时开始驱动LED打开或关闭。这只是关闭pir传感器,以便在白天不打开LED。
顺便说一下,在这个单独的配置中我只有一个pir传感器和一个LED,但我想只使用一个Python代码和一个LDR作为全局光传感器来管理4个pir传感器和4个LED。例如,所有的pir传感器都要等到天黑才开始作为输入工作,当天黑时,每个pir传感器都可以控制一个特定的LED
pir1 = led1,pir2 = led2,pir3 = led3,pir4 = led4
这是pir传感器和led的代码:
import RPi.GPIO as GPIO
import time
GPIO.setmode(GPIO.BCM)
GPIO.setwarnings(False)
GPIO.setup(21, GPIO.IN) #pir sensor put as input
GPIO.setup(25, GPIO.OUT) # led put as output
GPIO.output(25, GPIO.LOW)
delay = 10 # set number of seconds delay before light turns off
while True:
#wait for pir to trigger.
print "waiting "
while GPIO.input(21) == 0:
time.sleep (0.5)
print "turn light on here"
GPIO.output(25, GPIO.HIGH)
count = 0
#start count down to turn off
print "count down started "
while count < delay:
count = count + 1
# here if the input goes high again we reset the counter to 0
if GPIO.input(21) == 1:
count = 0
print "count down now ", (delay - count)
time.sleep(1)
print "Turn light off"
GPIO.output(25, GPIO.LOW)
ldr传感器和led的代码在哪里:
import RPi.GPIO as GPIO
import time
GPIO.setmode(GPIO.BCM)
delayt = .1
value = 0 # this variable will be used to store the ldr value
ldr = 12 #ldr is connected with pin number 12
led = 25 #led is connected with pin number 25
GPIO.output(led, False) # keep led off by default
def rc_time (ldr):
count = 0
#Output on the pin for
GPIO.setup(ldr, GPIO.OUT)
GPIO.output(ldr, False)
time.sleep(delayt)
#Change the pin back to input
GPIO.setup(ldr, GPIO.IN)
#Count until the pin goes high
while (GPIO.input(ldr) == 0):
count += 1
return count
#Catch when script is interrupted, cleanup correctly
try:
# Main loop
while True:
print("Ldr Value:")
value = rc_time(ldr)
print(value)
if ( value >= 70):
print("It is dark turn on led")
GPIO.output(led, True)
if (value < 69):
print("It is light turn off led")
GPIO.output(led, False)
except KeyboardInterrupt:
pass
finally:
GPIO.cleanup()
任何帮助都非常感谢。记住我是Python编码真的Noob。我所有的工作都是经过反复试验。
我认为下面的代码可以工作......我没有雇用,因为我无法测试这个,但试一试。
import RPi.GPIO as GPIO
import time
GPIO.setmode(GPIO.BCM)
GPIO.setwarnings(False)
GPIO.setup(21, GPIO.IN) #pir sensor put as input
GPIO.setup(25, GPIO.OUT) # led put as output
GPIO.setup(12, GPIO.OUT)
GPIO.output(12, False)
GPIO.output(25, False) # keep led off by default
delayt = .1
ldr = 12 #ldr is connected with pin number 12
led = 25 #led is connected with pin number 25
delay = 10 # set number of seconds delay before light turns off
def is_dark():
global ldr, led, delayt
count = 0
#Output on the pin for
GPIO.setup(ldr, GPIO.OUT)
GPIO.output(ldr, False)
time.sleep(delayt)
#Change the pin back to input
GPIO.setup(ldr, GPIO.IN)
#Count until the pin goes high
while (GPIO.input(ldr) == 0):
count += 1
if count >= 70:
return True
return False
def has_someone():
if GPIO.input(21) == 1:
return True
return False
def main():
global delay
while True:
if has_someone() and is_dark():
print "turn light on here"
GPIO.output(25, GPIO.HIGH)
count = 0
while count < delay:
count = count + 1
# here if the input goes high again we reset the counter to 0
if has_someone() == 1:
count = 0
print "count down now ", (delay - count)
time.sleep(1)
print "Turn light off"
GPIO.output(25, GPIO.LOW)
if __name__ == "__main__":
try:
main()
except KeyboardInterrupt:
pass
finally:
GPIO.cleanup()