@JsonProperty 未按预期工作

Question

当我使用 Spring RestTemplate 使用静态 Web 服务时，出现以下异常

com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "IMP-SourceTxnId" (class com.model.ResponseBaseParameters) not marked as ignorable (4 known properties: , "sourceTxnId", "incommTxnId", "responseCode", "responseText"])

at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@2f2ddd7c; line: 1, column: 130] (through reference chain: com.incomm.ife.model.rogers.RogersTransactionResponse["responseBaseParameters"]->com.incomm.ife.model.rogers.ResponseBaseParameters["IMP-SourceTxnId"])
at com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:79)
at com.fasterxml.jackson.databind.DeserializationContext.reportUnknownProperty(DeserializationContext.java:555)
at com.fasterxml.jackson.databind.deser.std.StdDeserializer.handleUnknownProperty(StdDeserializer.java:708)
at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownProperty(BeanDeserializerBase.java:1159)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserializeFromObject(BeanDeserializer.java:315)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:121)
at com.fasterxml.jackson.databind.deser.SettableBeanProperty.deserialize(SettableBeanProperty.java:449)
at com.fasterxml.jackson.databind.deser.impl.MethodProperty.deserializeAndSet(MethodProperty.java:98)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserializeFromObject(BeanDeserializer.java:295)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:121)
at com.fasterxml.jackson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:2888)
at com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:2094)
at org.springframework.http.converter.json.MappingJackson2HttpMessageConverter.readInternal(MappingJackson2HttpMessageConverter.java:123)
... 54 more

响应参数为

{

  "responseBaseParameters":  

{

  "responseCode": "32",

  "responseText": "Invalid Request",

  "incommTxnId": null,

  "IMP-SourceTxnId": "551932ba-6af4-44f9-ab98-db5bc96e962b"

 }

}

我的 POJO 类是

public class ResponseBaseParameters {

private String responseCode;

private String responseText;
private String incommTxnId;
@JsonProperty("IMP-SourceTxnId")
private String sourceTxnId;

public String getResponseCode() {
    return responseCode;
}

public void setResponseCode(String responseCode) {
    this.responseCode = responseCode;
}

public String getResponseText() {
    return responseText;
}

public void setResponseText(String responseText) {
    this.responseText = responseText;
}

public String getIncommTxnId() {
    return incommTxnId;
}

public void setIncommTxnId(String incommTxnId) {
    this.incommTxnId = incommTxnId;
}

public String getSourceTxnId() {
    return sourceTxnId;
}

public void setSourceTxnId(String sourceTxnId) {
    this.sourceTxnId = sourceTxnId;
}

}

请了解我为什么会收到此错误。谢谢

Answer 1

要通过 Jackson 映射您的 Json，您必须创建另一个包含 POJO 类的对象，有些像这样：

您的 POJO 类：

public static class ResponseBaseParameters {

    private String responseCode;
    private String responseText;
    private String incommTxnId;
    @JsonProperty("IMP-SourceTxnId")
    private String sourceTxnId;


    // Getter & Setter Methods...

}

然后是包含您的 POJO 类的类

ResponseBaseParameters

:

public class ResponseBase{


    @JsonProperty("responseBaseParameters")
    private ResponseBaseParameters responseBaseParameters;


    public ResponseBaseParameters getResponseBaseParameters() {
        return responseBaseParameters;
    }

    public void setResponseBaseParameters(ResponseBaseParameters responseBaseParameters) {
        this.responseBaseParameters = responseBaseParameters;
    }
}

如果你尝试这个，它会起作用

    public static void main(String[] args) throws JsonProcessingException {
        String s = """
                {
                  "responseBaseParameters":
                {
                  "responseCode": "32",
                  "responseText": "Invalid Request",
                  "incommTxnId": null,
                  "IMP-SourceTxnId": "551932ba-6af4-44f9-ab98-db5bc96e962b"
                 }
                }
                """;

        ResponseBase r =  JsonMapper.builder().build().readValue(s, ResponseBase.class);
        System.out.println(JsonMapper.builder().build().writerWithDefaultPrettyPrinter().writeValueAsString(r));
    }

输出是：

{
  "responseBaseParameters" : {
    "responseCode" : "32",
    "responseText" : "Invalid Request",
    "incommTxnId" : null,
    "IMP-SourceTxnId" : "551932ba-6af4-44f9-ab98-db5bc96e962b"
  }
}

如果您对此解决方案有任何疑问，请告诉我。