我跟随Rcpp Quick Reference Guide提取矩阵的一行作为矢量。该指南的示例是:
// Copy the second column into new object (xx is a NumericMatrix)
NumericVector zz1 = xx( _, 1);
当我在Rstudio中获取以下代码时,收到以下错误:
#include <Rcpp.h>
using namespace Rcpp;
// [[Rcpp::export]]
int foo1(Rcpp::IntegerVector res)
{
int output = res[0];
return output;
}
// [[Rcpp::export]]
int foo(Rcpp::IntegerMatrix res)
{
int n = res.nrow();
int output;
IntegerVector temp_res = res( 1, _);
// IntegerVector temp_res = res.row(1);
for (int r = 0; r < n; r++) {
output = foo1(res = temp_res); //////// Line 22
// output = foo1(res = as<IntegerVector>(temp_res));
}
return output;
}
为什么会出现此错误?如何从矩阵中提取所需的行并将其用于另一个函数,如上所示?
子集不是错误的来源。实际上,这是由于第一个错误而触发的更高版本的错误。
话虽如此,运行代码将产生:
fileb9516da5f592.cpp:22:23: error: no viable overloaded '='
output = foo1(res = temp_res); //////// Line 22
~~~ ^ ~~~~~~~~
/Library/Frameworks/R.framework/Versions/3.6/Resources/library/Rcpp/include/Rcpp/vector/Matrix.h:83:13: note: candidate function not viable: no known conversion from 'Rcpp::IntegerVector' (aka 'Vector<13>') to 'const Rcpp::Matrix<13, PreserveStorage>' for 1st argument
Matrix& operator=(const Matrix& other) {
^
/Library/Frameworks/R.framework/Versions/3.6/Resources/library/Rcpp/include/Rcpp/vector/Matrix.h:90:13: note: candidate function not viable: no known conversion from 'Rcpp::IntegerVector' (aka 'Vector<13>') to 'const SubMatrix<13>' for 1st argument
Matrix& operator=( const SubMatrix<RTYPE>& ) ;
^
1 error generated.
make: *** [fileb9516da5f592.o] Error 1
clang++ -std=gnu++11 -I"/Library/Frameworks/R.framework/Resources/include" -DNDEBUG -I"/Library/Frameworks/R.framework/Versions/3.6/Resources/library/Rcpp/include" -I"/private/var/folders/b0/vt_1hj2d6yd8myx9lwh81pww0000gn/T/RtmpRe7iKX/sourceCpp-x86_64-apple-darwin15.6.0-1.0.3" -isysroot /Library/Developer/CommandLineTools/SDKs/MacOSX.sdk -I/usr/local/include -fPIC -Wall -g -O2 -c fileb9516da5f592.cpp -o fileb9516da5f592.o
注意,第一个错误是:
fileb9516da5f592.cpp:22:23: error: no viable overloaded '='
output = foo1(res = temp_res); //////// Line 22
~~~ ^ ~~~~~~~~
由于命名参数传递,代码抛出错误。与R不同,C ++不支持命名参数。解决方法是使用位置参数。
即更改:
output = foo1(res = temp_res); //////// Line 22
至:
output = foo1(temp_res); //////// Line 22
Voila!
foo(matrix(1:4))
#[1] 2