我如何计算一行的列值大于另一列的分组对的数量?

问题描述 投票:0回答:1

我有一个带有多个成对值的数据集(df1)。该对中的一行是一年(例如2014年),另一行是另一年(例如2013年)。对于每对,在G列中都有一个值。我需要计算高年级的G值小于小年级的G值的对数。

这是我的数据集df1的输出:

structure(list(Name = c("A.J. Ellis", "A.J. Ellis", "A.J. Pierzynski", 
"A.J. Pierzynski", "Aaron Boone", "Adam Kennedy", "Adam Melhuse", 
"Adrian Beltre", "Adrian Beltre", "Adrian Gonzalez", "Alan Zinter", 
"Albert Pujols", "Albert Pujols"), Age = c(37, 36, 37, 36, 36, 
36, 36, 37, 36, 36, 36, 37, 36), Year = c(2018, 2017, 2014, 2013, 
2009, 2012, 2008, 2016, 2015, 2018, 2004, 2017, 2016), Tm = c("SDP", 
"MIA", "TOT", "TEX", "HOU", "LAD", "TOT", "TEX", "TEX", "NYM", 
"ARI", "LAA", "LAA"), Lg = c("NL", "NL", "ML", "AL", "NL", "NL", 
"ML", "AL", "AL", "NL", "NL", "AL", "AL"), G = c(66, 51, 102, 
134, 10, 86, 15, 153, 143, 54, 28, 149, 152), PA = c(183, 163, 
362, 529, 14, 201, 32, 640, 619, 187, 40, 636, 650)), row.names = c(NA, 
13L), class = "data.frame")

这里有一个小标题,显示了要检查的行的外观:https://www.dropbox.com/s/3nbfi9le568qb3s/grouped-pairs.png?dl=0

这是我用来创建小标题的代码:

df1 %>%
  group_by(Name) %>%
  filter(n() > 1)
r group-by
1个回答
1
投票

我们可以用arrangeNameAge数据,并检查last中的G值是否小于每个firstname值,并用sum计数那些出现的次数。] >

library(dplyr)
df %>%
  arrange(Name, Age) %>%
  group_by(Name) %>%
  summarise(check = last(G) < first(G)) %>%
  pull(check) %>%
  sum(., na.rm = TRUE)

#[1] 2

如果您希望较高年份的G值小于较小年份的G值的对,则可以使用filter

df %>%
  arrange(Name, Age) %>%
  group_by(Name) %>%
  filter(last(G) < first(G))

# Name              Age  Year Tm    Lg        G    PA
#  <chr>           <dbl> <dbl> <chr> <chr> <dbl> <dbl>
#1 A.J. Pierzynski    36  2013 TEX   AL      134   529
#2 A.J. Pierzynski    37  2014 TOT   ML      102   362
#3 Albert Pujols      36  2016 LAA   AL      152   650
#4 Albert Pujols      37  2017 LAA   AL      149   636
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