查找两个单词之间是否存在单词并在 JavaScript 中替换该单词

Question

我有类似的东西：

Some MY_WORD stupid txt='other text MY_WORD' and another MY_WORD  stupid text and txt='something else MY_WORD' and also txt='here nothing to replace' and here txt='again to replace MY_WORD here'

我想用

MY_WORD

替换

OTHER_WORD

，但前提是它位于

txt='

和

'

内部

/(?<=txt='.*)MY_WORD(?=.*')/g


Some MY_WORD stupid txt='other text OTHER_WORD' and another MY_WORD  stupid text and txt='something else OTHER_WORD' and also txt='here nothing to replace' and hexe txt='again to replace OTHER_WORD here'

但是并非所有浏览器都支持向后查找，因此这不是一个好方法。

A 尝试过这个，但即使它说有组匹配，我 3 美元是空的。

(txt=')((\.*)(MY_WORD))?

Answer 1

您可以使用一个简单的状态机来搜索和替换内部引号，这允许多次替换，并且不依赖于您所说的正则表达式，由于某种原因在感兴趣的浏览器中没有很好地支持：

const str = "Some MY_WORD stupid txt='other text MY_WORD' and another MY_WORD  stupid text and txt='something else MY_WORD' and also txt='here nothing to replace' and here txt='again to replace MY_WORD here and MY_WORD again '";

function replaceWordInQuotes(str, word, replace){
  const len = word.length;
  let insideQuotes = false, quoteIdx = 0;
  const found = [];
  while(true){
    const i = str.indexOf("'", quoteIdx);
    if(i < 0) break;
    if(insideQuotes){
      const wi = str.indexOf(word, quoteIdx);
      if(wi < 0) break;
      if(wi < i){
        found.push(wi);
        quoteIdx = wi + len;
        continue;
      }
    }
    insideQuotes = !insideQuotes;
    quoteIdx = i + 1;
  }

  console.log('found indices:', ...found);

  let result = '', prev = 0;
  for(const i of found){
    result += str.slice(prev, i) + replace;
    prev = i + len;
  }
  result += str.slice(prev);
  return result;
}

console.log(replaceWordInQuotes(str, 'MY_WORD', 'OTHER_WORD'));

Answer 2

您可以使用捕获组：

const str = "Some MY_WORD stupid txt='other text MY_WORD' and another MY_WORD  stupid text and txt='something else MY_WORD' and also txt='here nothing to replace' and here txt='again to replace MY_WORD here'";

const result = str.replace(/('[^']*)(?:MY_WORD)([^']*')/g, '$1OTHER_WORD$2');

console.log(result);