您会建议用什么来举起黑杰克手?

问题描述 投票:0回答:1

我是初学者,被要求(作为课程的一部分)构建一个黑杰克游戏。

我的初始代码可以在下面找到。当我到达Deck类并必须创建Deal方法时,我会遇到的问题。我正在努力的是如何处理最初的四张牌,如何将它们从卡组中可用的卡中删除(以备将来打中),然后还可以将它们存储为下一个课程中实际玩家手牌的变量。感谢帮助!

import random

suits = ('Hearts', 'Diamonds', 'Spades', 'Clubs')
ranks = ('Two', 'Three', 'Four', 'Five', 'Six', 'Seven', 'Eight', 'Nine', 'Ten', 'Jack', 'Queen', 'King', 'Ace')
values = {'Two':2, 'Three':3, 'Four':4, 'Five':5, 'Six':6, 'Seven':7, 'Eight':8, 'Nine':9, 'Ten':10, 'Jack':10,
         'Queen':10, 'King':10, 'Ace':11}

playing = True

class Card:

    def __init__(self,suit,rank,value):
        self.suit = suit
        self.rank = rank
        self.value = value

    def __str__(self):
        print(f'{rank} of {suit}')


class Deck:

    def __init__(self):
        self.deck = []  # start with an empty list
        for suit in range(len(suits)):
            for rank in range(len(ranks)):
                self.deck += [(suits[suit],values[ranks[rank]])]

    def __str__(self):
        return f'{self.deck}'

    def shuffle(self):
        random.shuffle(self.deck)

    def deal(self):
        ?????

python blackjack
1个回答
1
投票

我的建议是只弹出deal功能并返回一张卡,因为当玩家需要击打时,您会做很多事情:

def deal(self) -> Card:
    return self.deck.pop()

然后可以生成两张牌的两只手:

player_hand, dealer_hand = ([deck.deal() for _ in range(2)] for _ in range(2))

或者也许:

def deal_starting_hand(deck: Deck) -> List[Card]:
    """Deals a starting hand of two cards."""
    return [deck.deal() for _ in range(2)]

deck = Deck()
players = ["Player 1", "Dealer"]
player_hands = {player: deal_starting_hand(deck) for player in players}


如果您真的想拥有一个可以返回四张卡的函数,并且不想通过迭代弹出来完成,则可以:

four_cards = self.deck[:4]
self.deck = self.deck[4:]
return four_cards

但是,从学习和可读性的角度来看,IMO最好先具有较小的简单功能,然后使用它来构建更大的东西。

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