如何在js中使用箭头函数的2个条件使用对象的过滤器数组？ [重复]

Question

这个问题在这里已有答案：

• Filter array of objects by multiple properties and values 3回答

假设我有一个像这样的数组：

  const items=[{
        "taskType": "type2",
        "taskName": "two",
        "id": "19d0da63-dfd0-4c00-a13a-cc822fc81298"
      },
      {
        "taskType": "type1",
        "taskName": "two",
        "id": "c5385595-2104-409d-a676-c1b57346f63e"
      }]

我想要一个箭头（过滤器）函数，它返回除taskType = type2和taskName = 2之外的所有项目。那么在这种情况下，它只返回第二项？

Answer 1

你可以尝试否定Array.prototype.filter() 的条件

const items=[{
        "taskType": "type2",
        "taskName": "two",
        "id": "19d0da63-dfd0-4c00-a13a-cc822fc81298"
      },
      {
        "taskType": "type1",
        "taskName": "two",
        "id": "c5385595-2104-409d-a676-c1b57346f63e"
      }]

var res = items.filter(task => !(task.taskType == 'type2' && task.taskName == 'two'));

console.log(res);

Answer 2

你可以使用lodash的_.reject()。使用对象作为谓词，并通过以下方式定义要拒绝的属性和值：

const items= [{
  "taskType": "type2",
  "taskName": "two",
  "id": "19d0da63-dfd0-4c00-a13a-cc822fc81298"
},
{
  "taskType": "type3",
  "taskName": "two",
  "id": "19d0da63-dfd0-4c00-a13a-cc822fc81298"
},
{
  "taskType": "type1",
  "taskName": "two",
  "id": "c5385595-2104-409d-a676-c1b57346f63e"
}]

const result = _.reject(items, { taskType: "type2", taskName: "two" });

console.log(result);

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