我是VBA的新手。我有2个列表,一个价格列表和一个分配给该价格的概率列表。我需要根据概率组生成300个数字的列表。但是,我似乎无法正常工作。我从另一篇文章中摘录了代码:
Function RandItem(items As Variant, probs As Variant) As Variant
Dim i As Long, sum As Double
Dim spin As Double
spin = Rnd()
For i = LBound(probs) To UBound(probs)
sum = sum + probs(i)
If spin <= sum Then
RandItem = items(i)
Exit Function
End If
Next i
'if you get here:
RandItem = items(UBound(probs))
End Function
还有
Sub test()
Randomize
Dim i As Long, v As Variant
ReDim v(1 To 50)
For i = 1 To 50
v(i) = RandItem(Array(1, 2, 3, 4, 5), Array(0.26, 0.18, 0.26, 0.2, 0.1))
Next i
Debug.Print Join(v)
End Sub
以适应我的代码。但是,问题在于价格范围会扩大,并且概率会随时间而变化(由于历史权重)。所以我试图切换:
RandItem(Array(1, 2, 3, 4, 5), Array(0.26, 0.18, 0.26, 0.2, 0.1))
to
Dim i As Long, v As Variant
Dim LastRow As Long
Dim arrayPrice As Variant
Dim arrayProPrice As Variant
LastRow = Cells(Rows.Count, "A").End(xlUp).Row
arrayPrice = Range("A2:A" & LastRow).Value2
arrayProPrice = Range("B2:B" & LastRow).Value2
ReDim v(1 To 300)
For i = 1 To 300
v(i) = RandItem(arrayPrice, arrayProPrice)
Next i
Debug.Print Join(v)
End Sub
它返回:运行时错误“ 9”:下标超出范围。任何人都对如何解决此问题有任何建议,因此我可以使用数组变量而不是列出所有价格范围?
学分:Generating numbers with certain probabilities visual basics vba
您的动态解决方案不起作用,因为arrayPrice
和arrayProPrice
不是一维数组,正如[C0]期望的那样,而是二维数组。这是因为Excel Ranges通常可以具有多行和多列,因此RandItem
和.Value2
方法返回一个矩阵。
例如,如果您在Excel工作表中具有A2 = 1,A3 = 2和A4 = 3,则.Value
将为arrayPrice
。
在调用Array(Array(1), Array(2), Array(3))
之前,您首先必须将该矩阵展平为一维数组。 RandItem
也是如此。