3个Quicksort函数的中位数不起作用

问题描述 投票:0回答:1

我正在尝试获取以python实现的三个quicksort算法的中值,但无法弄清楚什么是错误的以及为什么它不起作用

from statistics import median

def Swap(arr, posA, posB):
    arr[posA], arr[posB] = arr[posB], arr[posA]

def Median(array):
    medianValue = median([array[0], array[int(len(array)/2)], array[-1]])
    return array.index(medianValue)

def Partition(array, start, end):
    pivot = array[end]
    i = start-1
    for j in range(start, end):
            if array[j] <= pivot:
                i += 1
                Swap(array, i, j)
    Swap(array, i+1, end)
    return i + 1

def Quicksort(array, startInd, endInd):
    if startInd < endInd:
        medianIndex = Median(array)
        Swap(array, medianIndex, endInd)
        pivot  = Partition(array, startInd, endInd)
        Quicksort(array, startInd, pivot  - 1)
        Quicksort(array, pivot  + 1, endInd)

感谢您的帮助:)

python algorithm sorting quicksort
1个回答
0
投票

问题是您从整个数组而不是正在处理的子节中获得3的中位数。可能的解决方法是:

将中位数函数更改为:

def Median(array, firstVal, middleVal, endVal):
    if (firstVal - middleVal) * (endVal - firstVal) >= 0:
        medianValue =  firstVal

    elif (middleVal - firstVal) * (endVal - middleVal) >= 0:
        medianValue = middleVal

    else:
        medianValue = endVal

    return array.index(medianValue)

然后将您的Quicksort函数更改为

def Quicksort(array, startInd, endInd):
    if startInd < endInd:
        # get median
        middleVal = (endInd + startInd) // 2
        medianIndex = Median(array, array[startInd], array[middleVal],
            array[endInd])
        #
        Swap(array, medianIndex, endInd)
        pivot  = Partition(array, startInd, endInd)
        Quicksort(array, startInd, pivot  - 1)
        Quicksort(array, pivot  + 1, endInd)
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