下面的命令在命令行模式下工作得很好
find . -maxdepth 1 -name "*.xlsx" -exec ssconvert {} --export-type=Gnumeric_stf:stf_csv \;
但是在SFTP下载代码后将其添加到Bash脚本文件中时,它没有执行。请帮忙。谢谢!
Bash脚本代码-
/usr/bin/expect<<EOD
spawn /usr/bin/sftp -o Port=${PORT} username@hostname
expect "password:"
send "$Pass_Pwd\r"
expect "sftp>"
send "lcd ${Src_Dir}\r"
expect "sftp>"
send "mget ${File1}\r"
expect "sftp>"
send "mget ${File1}\r"
expect "sftp>"
send "bye\r"
EOD
echo "Download done"
find . -maxdepth 1 -name "*.xlsx" -exec ssconvert {} --export-type=Gnumeric_stf:stf_csv \;
使用find可能会导致未执行的操作,因为它可能会产生不继承父变量的子流程。从我在您的代码中看到的,这不应该发生,但是:
无论如何,这是您可能想要编写的代码的强化示例:
workdir = /data/ftpdownloads
cd "$workdir" || { echo 'Failed to chdir into $workdir' ; exit 1; }
# Insert your expect script here
while IFS= read -r -d $'\0' file; do
ssconvert "$file" --export-type=Gnumeric_stf:stf_csv
done < <(find "$workdir" -type f -iname "*.xlsx" -print0)
免责声明:与bash一起使用:)