需要自动分页帮助

Question

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这对于那些提供了很好答案的人来说是赏金。

我有这个脚本：

<?php
if(urldecode($_SERVER['REQUEST_URI']) == "/?articles")
{
    include("Articles.php");
}
?>

这允许我设置页面的自定义URL。现在，当我需要像这样的URL时，就会发生问题：

/?articles | Page that contains newest articles which loads when user clicks "< Previous" button
/?articles&1 | Page that contains older articles which loads when user clicks "Next >" button
/?articles&2 | Page that contains older than older articles
/?articles&3 | Page that contains old articles
/?articles&4 | Page that contains old articles
/?articles&5 | Page that contains oldest articles
/?articles&6 | Page that contains oldest articles, also last page in the pagination

依此类推。即，上面脚本中的代码将如下所示：

if(urldecode($_SERVER['REQUEST_URI']) == "/?articles&1")
{
    include("Articles-500.php");
}
if(urldecode($_SERVER['REQUEST_URI']) == "/?articles&2")
{
    include("Articles-499.php");
}
if(urldecode($_SERVER['REQUEST_URI']) == "/?articles&3")
{
    include("Articles-498.php");
}
if(urldecode($_SERVER['REQUEST_URI']) == "/?articles&4")
{
    include("Articles-497.php");
}
if(urldecode($_SERVER['REQUEST_URI']) == "/?articles&5")
{
    include("Articles-496.php");
}
if(urldecode($_SERVER['REQUEST_URI']) == "/?articles&6")
{
    include("Articles-495.php");
}

但是每次具有最新文章的页面被填充（每页包含10条文章时，我必须像这样更新脚本：

if(urldecode($_SERVER['REQUEST_URI']) == "/?articles&1")
{
    include("Articles-505.php");
}
if(urldecode($_SERVER['REQUEST_URI']) == "/?articles&1")
{
    include("Articles-504.php");
}
if(urldecode($_SERVER['REQUEST_URI']) == "/?articles&1")
{
    include("Articles-503.php");
}
if(urldecode($_SERVER['REQUEST_URI']) == "/?articles&1")
{
    include("Articles-501.php");
}
if(urldecode($_SERVER['REQUEST_URI']) == "/?articles&1")
{
    include("Articles-500.php");
}

Answer 1

您可以做的是，为了动态创建此文件，请使用功能glob，该功能可以列出目录中的所有文件。

鉴于我将拥有这些文件：

• Articles-1.php
• Articles-2.php
• Articles-3.php
• ...

而且，在默认情况下，glob按字母顺序对路径名进行排序，这意味着我们将不得不通过glob反转生成的文件数组。

array_reverse

这应该给您动态包含的权利。