正则表达式在Swift中获取一对方括号之间的文本

Question

<strong>Lorem Ipsum.<\/strong> Lorem Ipsum. [link-to:shop-page \"instore-pickup\"]Learn More[\/link-to]

给出上面的示例字符串（包括HTML），该字符串是我从第三方服务获得的，因此无法改善或标准化它以适合HTML标准。

我需要以某种方式解析此部分[link-to:shop-page \"instore-pickup\"]Learn More[\/link-to]以获取Learn More值。

我已经尝试过\\[.*?\\](.*?)\\[.*?\\]正则表达式，但是它不能满足我的需要。结果为[link-to:shop-page \"instore-pickup\"]Learn More[/link-to]。

func matches(for regex: String, in text: String) -> [String] {
    do {
        let regex = try NSRegularExpression(pattern: regex)
        let nsString = text as NSString
        let results = regex.matches(in: text, range: NSRange(location: 0, length: nsString.length))
        return results.map { nsString.substring(with: $0.range)}
    } catch let error {
        print("invalid regex: \(error.localizedDescription)")
        return []
    }
}

Answer 1

Wiktor，感谢您指出，正在运行的摘要：

func matches(for regex: String, in text: String) -> [String] {
    do {
        let regex = try NSRegularExpression(pattern: regex)
        let nsString = text as NSString
        let results = regex.matches(in: text, range: NSRange(location: 0, length: nsString.length))
        return results.map { nsString.substring(with: $0.range(at: 1))}
    } catch let error {
        print("invalid regex: \(error.localizedDescription)")
        return []
    }
}

[$0.range(at: 1)给出第1组。