当用户迅速单击推送通知时打开自定义URL

Question

我正在尝试使用WKWebView和Firebase Push开发IOS / Swift应用程序。我想使用PHP发送通知，并且当用户单击通知以在Webview中打开自定义URL时发送通知。默认网址是

let url = URL(string: "https://mywebsite.com/index.php?token=\(token)")!

而且我想在这个URL中传递这样的ID

let url = URL(string: "https://client.gazduire.net/app3/index.php?token=\(token)&ntid=(id that is send with push notification, ex.:1)")!

我在appdelegate.swift中的代码

 func userNotificationCenter(_ center: UNUserNotificationCenter,didReceive response: UNNotificationResponse,
withCompletionHandler completionHandler: @escaping () -> Void) {
let userInfo = response.notification.request.content.userInfo
// Print message ID.
if let messageID = userInfo[gcmMessageIDKey] {
  print("Message ID: \(messageID)")
}
// Print full message.
print(userInfo)

let notificationName = Notification.Name("test")
NotificationCenter.default.post(name: notificationName, object: nil,userInfo: userInfo)

let ntid = userInfo["ntid"] as! String
print("\(ntid)")


completionHandler()

}

ViewController.swift

@objc func test() {
    let appDelegate = UIApplication.shared.delegate as! AppDelegate
    let ntid = appDelegate.ntid
    let token = Messaging.messaging().fcmToken


guard let url = URL(string: "https://mywebsite.com/index.php?token=\(token ?? "")&ntid=\(ntid)")      else {
   print("Invalid URL")
   return
   }

    let request = URLRequest(url: url)
    webView.load(request)
}

当用户点击推送通知时，我可以从appdelegate向视图控制器发送ntid（ntid已被接收并正确打印吗？谢谢！

Answer 1

以一种简单的方式，只需在视图控制器的层次结构中找到您的视图控制器，将“ ntid”值传递给存储的属性并调用“测试”方法。

Answer 2

首先将枚举定义为

enum Identifiers {
  static let viewAction = "cat1"
  static let newsCategory = "cat2"
}

然后在您的UNUserNotificationCenterDelegate中>

extension AppDelegate: UNUserNotificationCenterDelegate {
  func userNotificationCenter(
    _ center: UNUserNotificationCenter,
    didReceive response: UNNotificationResponse,
    withCompletionHandler completionHandler: @escaping () -> Void) {

    // 1
    let userInfo = response.notification.request.content.userInfo

    // 2
    if let aps = userInfo["aps"] as? [String: AnyObject],
      let newsItem = NewsItem.makeNewsItem(aps) {

      (window?.rootViewController as? UITabBarController)?.selectedIndex = 1

      // 3
      if response.actionIdentifier == Identifiers.viewAction,
        let url = URL(string: newsItem.link) {
        let safari = SFSafariViewController(url: url)
        window?.rootViewController?.present(safari, animated: true,
                                            completion: nil)
      }
    }

    // 4
    completionHandler()
  }
}
像这样在您的推送服务中添加类别

{
  "aps": {
    "alert": "messaga",
    "sound": "default",
    "link_url": "www.google.com",
    "category": "cat1",

  }
}
它将检查aps类型，然后按类别类型1或2推送视图控制器。您可以通过这种方式添加任意数量的]