我有以下脚本:
SELECT DISTINCT GIFT_ID, GIFT_DESG, SUM(GIFT_AMT)
FROM GIFT_TABLE
GROUP BY GIFT_ID, GIFT_DESG
它将返回如下内容:
GIFT_ID GIFT_DESG SUM(GIFT_AMT)
1 A 25
1 B 500
1 C 75
2 A 100
2 B 200
2 C 300
...
我期望的结果是:
GIFT_ID GIFT_DESG SUM(GIFT_AMT)
1 B 500
2 C 300
我该怎么办?
可能是row_number()对吗?我认为通过指定的礼物金额的总和会让我失望。
谢谢。
如果您的DBMS支持ROW_NUMBER
窗口函数,您可以尝试通过GIFT_ID
按SUM(GIFT_AMT)
顺序排序,然后获取rn = 1
行。
SELECT t1.GIFT_ID,t1.GIFT_DESG,t1.GIFT_AMT
FROM (
SELECT t1.*,ROW_NUMBER() OVER(PARTITION BY GIFT_ID ORDER BY GIFT_AMT DESC) rn
FROM (
SELECT GIFT_ID, GIFT_DESG, SUM(GIFT_AMT) GIFT_AMT
FROM GIFT_TABLE
GROUP BY GIFT_ID, GIFT_DESG
) t1
) t1
where rn =1
注意
您已经使用GROUP BY
DISTINCT
关键字是没有意义的,您可以从查询中删除它。
这是一个例子
CREATE TABLE T(
GIFT_ID int,
GIFT_DESG varchar(5),
GIFT_AMT int
);
insert into t values (1,'A' ,25);
insert into t values (1,'B' ,500);
insert into t values (1,'C' ,75);
insert into t values (2,'A' ,100);
insert into t values (2,'B' ,200);
insert into t values (2,'C' ,300);
查询1:
SELECT t1.GIFT_ID,t1.GIFT_DESG,t1.GIFT_AMT
FROM (
SELECT t1.*,ROW_NUMBER() OVER(PARTITION BY GIFT_ID ORDER BY GIFT_AMT DESC) rn
FROM T t1
) t1
where rn =1
| GIFT_ID | GIFT_DESG | GIFT_AMT |
|---------|-----------|----------|
| 1 | B | 500 |
| 2 | C | 300 |
您可以在没有子查询的情况下执行此操作:
SELECT TOP (1) WITH TIES GIFT_ID, GIFT_DESG, SUM(GIFT_AMT)
FROM GIFT_TABLE
GROUP BY GIFT_ID, GIFT_DESG
ORDER BY ROW_NUMBER() OVER (PARTITION BY GIFT_ID ORDER BY SUM(GIFT_AMT) DESC);
你也可以这样做
WITH t as
SELECT GIFT_ID, GIFT_DESG, SUM(GIFT_AMT) AS GIFT_AMT
FROM GIFT_TABLE
GROUP BY GIFT_ID, GIFT_DESG)
SELECT GIFT_ID,
max(GIFT_DESG) KEEP (DENSE_RANK LAST ORDER BY GIFT_AMT),
max(GIFT_AMT) GIFT_AMT
FROM T
GROUP BY GIFT_ID;