对于表a中的每个记录，返回表b中日期最接近但现在大于NOW（）的记录

Question

服务器版本：10.3.15-MariaDB-log

我有这样的数据结构

TABLE A - Participant

participantID
--------------
1
2
3
4

TABLE B - Appointment

appointmentID | participantID | locationID | beginDateTime
----------------------------------------------------------------
1             | 1             | 1          | 2019-10-09 11:00:00
2             | 1             | 1          | 2019-10-10 11:00:00
3             | 2             | 2          | 2019-10-11 11:00:00
4             | 3             | 3          | 2019-11-09 11:00:00
5             | 5             | 1          | 2019-10-15 11:00:00

TABLE C - Location

locationID | locationTypeID
----------------------------
1          | 1
2          | 2
3          | 3

TABLE D - Location Type

locationTypeID | locationType
-----------------------------
1              | mobile
2              | onsite
3              | unknown

我只希望获得将来约会的参与者，如果他们未来约会的位置是移动位置类型，我只想返回这些参与者。但是，我只关心他们最近的约会地点。我需要在单个查询中执行此操作。我已经到了这个阶段，在这里我可以获取所有地点的locationType，对于所有比现在更大的约会，对于所有人，但是我需要将其限制为仅在最近的约会中，并且不确定如何继续。

SELECT p.participantID
FROM locationType AS lt
LEFT JOIN location AS l ON l.locationTypeID = lt.locationTypeID
LEFT JOIN appointment AS a ON a.locationID = l.locationID
LEFT JOIN participant AS p ON p.participantID = a.participantID
WHERE p.participantID IN (
    SELECT a.participantID
    FROM appointment AS a
    LEFT JOIN location AS l ON l.locationID = a.locationID
    LEFT JOIN locationType AS lt ON lt.locationTypeID = l.locationTYpeID
    WHERE a.beginDateTime > NOW()
    AND l.locationTypeID IN (
        SELECT locationTypeID 
        FROM locationType 
        WHERE locationType = 'mobile'
    )
);

Answer 1

MariaDB 10.3支持Window Functions；因此，一种方法是根据您的要求简单地联接表，然后以beginDateTime的升序计算行号。之后，您可以将结果用作子查询，并仅考虑行号为1的那些行。]

ROW_NUMBER() OVER(PARTITION BY p.participantID ORDER BY a.beginDateTime ASC)：将具有相同p.participantID值的所有行分区在一起。就像GROUP BY，但是这里的主要区别是GROUP BY将它们聚合为单个行，而PARTITION BY将它们维护为单独的行。现在，在p.participantID特定值的特定分区内，它以beginDateTime值的升序将行号分配给各个行。因此，具有最低beginDateTime值的行将得到行号= 1，第二最低的是2，依此类推。依此类推。由于您需要最近的日期时间行，因此我们可以简单地考虑行号为1的行。

SELECT * FROM 
(
  SELECT p.participantID, 
         ROW_NUMBER() OVER(PARTITION BY p.participantID 
                           ORDER BY a.beginDateTime ASC) AS rn
  FROM locationType AS lt
  JOIN location AS l ON l.locationTypeID = lt.locationTypeID
  JOIN appointment AS a ON a.locationID = l.locationID 
                           AND a.beginDateTime > NOW() 
  JOIN participant AS p ON p.participantID = a.participantID 
  WHERE lt.locationType = 'Mobile'
) dt 
WHERE rn = 1