运算符==不能应用于Kotlin中的'Long'和'Int'

Question

我正在尝试在Kotlin中实现Mike Penz的NavigationDrawer（https://github.com/mikepenz/MaterialDrawer）的部分内容。从那以后，我遇到了一些问题，主要是运营商。以下是实例化抽屉本身的代码的一部分。 Android Studio不会抛出任何错误，除非我在int和Long变量上使用==运算符：

        // Create the Drawer
        result = DrawerBuilder()
                .withSliderBackgroundColor(ContextCompat.getColor(applicationContext, R.color.top_header))
                .withActivity(this)
                .withToolbar(toolbar)
                .withHasStableIds(true)
                .withItemAnimator(AlphaCrossFadeAnimator())
                .withAccountHeader(headerResult!!)
                .addDrawerItems(
                        PrimaryDrawerItem().withName(R.string.drawer_item_profile).withIcon(FontAwesome.Icon.faw_user).withIdentifier(1).withSelectable(false).withIconColor(ContextCompat.getColor(applicationContext, R.color.icon_grey)).withTextColor(ContextCompat.getColor(applicationContext, R.color.stroke)),
                        PrimaryDrawerItem().withName(R.string.drawer_item_create).withIcon(FontAwesome.Icon.faw_paint_brush).withIdentifier(2).withSelectable(false).withIconColor(ContextCompat.getColor(applicationContext, R.color.icon_grey)).withTextColor(ContextCompat.getColor(applicationContext, R.color.stroke)),
                        PrimaryDrawerItem().withName(R.string.drawer_item_yaanich_news).withIcon(FontAwesome.Icon.faw_newspaper_o).withIdentifier(3).withSelectable(false).withIconColor(ContextCompat.getColor(applicationContext, R.color.icon_grey)).withTextColor(ContextCompat.getColor(applicationContext, R.color.stroke)),
                        PrimaryDrawerItem().withName(R.string.drawer_item_my_groups).withIcon(FontAwesome.Icon.faw_users).withIdentifier(4).withSelectable(false).withIconColor(ContextCompat.getColor(applicationContext, R.color.icon_grey)).withTextColor(ContextCompat.getColor(applicationContext, R.color.stroke)),
                        PrimaryDrawerItem().withName(R.string.drawer_item_settings).withIcon(FontAwesome.Icon.faw_cog).withIdentifier(5).withSelectable(false).withIconColor(ContextCompat.getColor(applicationContext, R.color.icon_grey)).withTextColor(ContextCompat.getColor(applicationContext, R.color.stroke))
                )
                .withOnDrawerItemClickListener { view, position, drawerItem ->

                    if (drawerItem != null) {
                        var intent: Intent? = null
                        if (drawerItem.identifier == (1) {
                            intent = Intent(this, UserProfileActivity::class.java)
                        } else if (drawerItem.identifier == 2) {
                            intent = Intent(this, YeetActivity::class.java)
                        } else if (drawerItem.identifier == 3) {
                            intent = Intent(this, RssActivity::class.java)
                        } else if (drawerItem.identifier == 4) {
                            intent = Intent(this, GroupsActivity::class.java)
                        } else if (drawerItem.identifier == 5) {
                            intent = Intent(this, UserSettingsActivity::class.java)
                        }
                        if (intent != null) {
                            this.startActivity(intent)
                        }
                    }
                    false
                }
                .withSavedInstance(savedInstanceState)
                .withShowDrawerOnFirstLaunch(true)
                .build()

        RecyclerViewCacheUtil<IDrawerItem<*, *>>().withCacheSize(2).apply(result!!.recyclerView, result!!.drawerItems)

        if (savedInstanceState == null) {
            result!!.setSelection(21, false)
            headerResult!!.activeProfile = profile
        }
    }

错误：

if (drawerItem.identifier == (1)

if (drawerItem.identifier == 2)

Operator == cannot be applied to 'Long and' 'Int'

Answer 1

只需在右侧使用很长时间即可

if (drawerItem.identifier == 1L)

编辑：这是必要的原因是Kotlin不会将Ints推广到Longs（或者更常见的是，不会扩展类型）;在左侧我们有一个Long，在右侧我们有一个Int，导致错误。明确指示右侧是Long修复错误。

Answer 2

为了兴趣，另一个解决方案是使用compareTo()。如果值相等，compareTo返回零，如果小于另一个则返回负数，如果大于另一个则返回正数：

 if(drawerItem.identifier.compareTo(1) == 0)   "Equals"

Answer 3

如果你遇到<operator！=不适用于long和int>的问题解决它只需在你的右边使用long即值！= 1L就是这样...