此问题已经在这里有了答案:
是否有这样的简写方式(可能是番石榴或任何lib)来初始化Java List?
List list = MagicListUtil.newArrayList(firstElement, moreElementsList);
Lists.asList(...)
Lists.asList(...)
String first = "first";
String[] rest = { "second", "third" };
List<String> list = Lists.asList(first, rest);
,请使用Iterables
:FluentIterable.of(...).append(...).toList()
尽管,虽然更冗长,但仍然...
FluentIterable.of(...).append(...).toList()
String first = "first";
List<String> rest = Arrays.asList("second", "third");
List<String> list = FluentIterable.of(first).append(rest).toList();
是的,您可以简单地将java.util.Arrays类用于单个和多个元素。
String first = "first";
String[] rest = { "second", "third" };
List<String> list = Stream.concat(Stream.of(first), Arrays.stream(rest))
.collect(Collectors.toList());
您可以将java.util.Collections用于具有单个元素的列表。
String first = "first";
List<String> rest = Arrays.asList("second", "third");
List<String> list = Stream.concat(Stream.of(first), rest.stream())
.collect(Collectors.toList());
如果您想复制列表,可以像这样由构造函数来完成
List<String> strings = Arrays.asList("first", "second", "third");