tk 窗口在使用 after 方法时崩溃

Question

我正在尝试制作一个 madlibs 应用程序，所以我在 Python 中为

input()

制作了一个 GUI，但是当我尝试这样做时，该函数没有运行，GUI 甚至没有出现！有人可以帮我吗？ 这是我的代码：

import tkinter as tk

app=tk.Tk()
d=None
def check():
    if d != None:
      return
    else:
      app.after(10, check)



app.title("Vacation MadLibs")
def help():
  helpWindow = tk.Toplevel(app) 
  tk.Label(helpWindow, text="How to play:\nThis game is called MadLibs!\nYou will be asked a series of questions that you will have\nto answer. After you are done answering the questions we\nwill show you a story that you created!").pack()
tk.Button(app,text="How to play",command= help).pack()
label=tk.Label(app,text="")


textbox=tk.Text(app, height= 1, width= 6 )

def enter():
  global d
  d = textbox.get("1.0","end")

button=tk.Button(app,command= enter)



def getInput(text):
  
  label.pack()
  textbox.pack()
  button.pack()
  check()
  label["text"]=text
  

answer1= getInput("Name an emotion....   ")
answer2= getInput("Name a place....   ")
answer3= getInput("Name a person....    ")
answer4= getInput("Name a vehicle....   ")
answer5= getInput("Name a number....    ")
answer6= getInput("Name another number....    ")
answer7= getInput("Name a verb....    ")
answer8= getInput('Name an adjective....    ')
answer9= getInput("Name an animal...    ")
answer10= getInput("Name another adjective....   ")
answer11= getInput("Name a food...    ")
answer12= getInput("Name an emotion...   ")
answer13= getInput("Name a famous person....     ")
answer14= getInput("Name an adjective....   ")

print("This is your story...")
print("Im so " + answer1)
print("Today we are going on a vacation to " + answer2)
print("Im going with " + answer3)
print("and we will travel there by " + answer4)
print ("The journey will take " + answer5 )
print ("hours and we will stay there for " + answer6)
print("days. After we arrived we decided to  " + answer7)
print("Then we saw a " + answer8)
print(answer9)
print("We were starving so we decided to eat a " + answer10)
print(answer11)
print("We were so " + answer12)
print("Because we met " + answer13)
print("Overall the vacation was really " + answer14 )

我在网上看到，如果我使用 after 方法，我的应用程序不会崩溃，但它会崩溃。

Answer 1

这根本不是如何从用户那里获得输入。 GUI 开发的本质意味着程序总是在循环中运行以等待事件，因此您无需创建自己的循环。

相反，您可以使用 tkinter 的

wait_variable

方法等待变量设置。您可以在用户单击按钮或按下返回键时设置该变量。

wait_variable

与

mainloop

类似，只是它会在设置变量后立即自动返回。然而，像

mainloop

一样，它会监听和响应事件。

它可能看起来像这样：

import tkinter as tk

def getInput(prompt):
    label.configure(text=prompt)
    textbox.delete("1.0", "end")

    label.pack()
    textbox.pack()
    button.pack()

    textbox.wait_variable(var)
    return var.get()

def enter(event=None):
    var.set(textbox.get("1.0", "end-1c"))

app=tk.Tk()
app.title("Vacation MadLibs")

var = tk.StringVar()
label=tk.Label(app,text="")
textbox=tk.Text(app, height= 1, width= 6 )
button=tk.Button(app,command= enter)

textbox.bind("<Return>", enter)

answer1= getInput("Name an emotion....   ")
answer2= getInput("Name a place....   ")
...